Pass initial array values uses curly braces

Question

Is there a way to pass an array to a function using its initial curly brace values?

For Example:

void doSomething(?)
{
    array[5] = ?;
}

int main()
{
    doSomething({1,2,3,4,5});
    return 0;
}

By the way, I don't think I can include initializer_list with VS 2012, I don't believe it exists. Supposedly I hear it's useful for these cases.

score 0 · Accepted Answer · answered Dec 15 '14 at 06:30

0

You cannot include initializer_list in VS 2012, because it's not available in that version. Microsoft added it with VS2013. See http://msdn.microsoft.com/en-us/library/vstudio/hh567368(v=vs.120).aspx

answered Dec 15 '14 at 06:30

Martin

911
5
7

Oh, well thanks for clearing that up, I wasn't 100% sure if the header actually didn't exist. – Blah blah blah Dec 15 '14 at 06:53

score 0 · Answer 2 · answered Dec 15 '14 at 06:38

List initialization is only available since C++11. Passing a braced init list as a function argument tries to list initialize the corresponding argument. Thus, any type which can be list initialized would be a valid argument type for your case. In particular, aggregate types, initializer_list-constructible types and types with a constructor matching the types in the braced init list(non-narrowing conversions only) would work.

Here are a few possible signatures for doSomething:

void doSomething(initializer_list<int>);
void doSomething(vector<int>);

struct Agg
{
  int a,b,c,d,e;
};
void doSomething(Agg);

struct Constructible
{
Constructible(int, int, int, int, int);
};
void doSomething(Constructible);

Pass initial array values uses curly braces

2 Answers2