simpledateformat getting parsing exceptiong using java

Question

My input is 2014-12-12T10:39:40Z. I want output like 12//11/2014 8:58:15 AM. here i am using

SimpleDateFormat formatter = new SimpleDateFormat("dd/MM/yyyy'T' HH:mm:ss 'a'");

But i am geting parsing exception. let me know how to write simpledateformat.

Advance Thanks Srinivas B

Post the snippet, parse from and parse true. I think you are mixing the two. — Subir Kumar Sao, Dec 15 '14 at 07:24
Check out the [docs](http://docs.oracle.com/javase/7/docs/api/java/text/SimpleDateFormat.html) for Date and Time patterns. — default locale, Dec 15 '14 at 07:25
The pattern you're using, which we don't know if it's used to parse your input, or generate your output, doesn't match any of your dates. — JB Nizet, Dec 15 '14 at 07:26

score 1 · Answer 1 · answered Dec 15 '14 at 07:24

1

you need two DateFormatter one to match your input pattern then second one to format it in the format you need, You are parsing input with your output SimpleDateFormat

answered Dec 15 '14 at 07:24

jmj

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score 1 · Answer 2 · answered Dec 15 '14 at 07:28

If your input date is a String, then first you need to parse that to convert to a Date. You can use a SimpleDateFormat object for that.

Then, to output in the format you want, you need another SimpleDateFormat object.

Something like this:

    String input = "2014-12-12T10:39:40Z";
    SimpleDateFormat parser = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ss'Z'");
    Date date = parser.parse(input);
    SimpleDateFormat formatter = new SimpleDateFormat("dd/MM/yyyy H:mm:ss a");
    System.out.println(formatter.format(date));

score 1 · Answer 3 · edited May 23 '17 at 11:57

You're input appears to be ISO8601, so you can use DatatypeConverter. There are issues parsing 8601 dates using SimpleDateFormat, see Converting ISO 8601-compliant String to java.util.Date

SimpleDateFormat output = new SimpleDateFormat(
        "dd/MM/yyyy'T' HH:mm:ss 'a'");
Date input = javax.xml.bind.DatatypeConverter.parseDateTime(
        "2014-12-12T10:39:40Z").getTime();

System.out.println(output.format(input));

Java 8 using new time API

LocalDateTime localDateTime = LocalDateTime.parse("2014-12-12T10:39:40Z",
        DateTimeFormatter.ISO_DATE_TIME);

Date utilDate =  Date.from(localDateTime.atZone(ZoneId.systemDefault()).toInstant());
System.out.println(output.format(utilDate));

score 1 · Answer 4 · answered Dec 15 '14 at 07:29

1

SimpleDateFormat formatter = new SimpleDateFormat("dd/MM/yyyy'T' HH:mm:ss a");
SimpleDateFormat formatter1 = new SimpleDateFormat("yyyy-MM-dd'T'hh:mm:ss");

System.out.println(formatter.format(formatter1.parse("2014-12-12T10:39:40'a'")));

answered Dec 15 '14 at 07:29

Siva Kumar

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score 1 · Answer 5 · answered Dec 15 '14 at 07:30

Try this:

String input = "2014-12-12T10:39:40Z";
SimpleDateFormat parser = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ss'Z'");
Date date = parser.parse(input);
SimpleDateFormat formatter = new SimpleDateFormat("dd/MM/yyyy hh:mm:ss aaa");
System.out.println(formatter.format(date));

simpledateformat getting parsing exceptiong using java

5 Answers5