Python zipfile whole path is in file

Question

I'm using the code from here to make a zip file from a directory. I give the function an absolute path to a folder from a GUI. Currently, say the path is c:\users......, the zip folder structure is users...... .

How can I remove the absolute path bits and just have the end folder of the path being used for the zip file? I understand that the result is right, because what I'm describing is the result from os.walk but I want to strip out the absolute path.

def zipdir(path, zip):
    for root, dirs, files in os.walk(path):
        for file in files:
            zip.write(os.path.join(root, file))

mhawke · Accepted Answer · 2014-12-15T14:08:55.780

1

Do this:

def zipdir(path, zip):
    path = os.path.abspath(path)
    for root, dirs, files in os.walk(path):
        dest_dir = root.replace(os.path.dirname(path), '', 1)
        for file in files:
            zip.write(os.path.join(root, file), arcname=os.path.join(dest_dir, file))

This converts the given path to an absolute path, the directory name of which is used to remove the leading path component in root.

edited Dec 15 '14 at 14:08

answered Dec 15 '14 at 12:38

mhawke

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Thanks for the answer, but I need to preserve the file structure. I essentially want to pass an absolute path for the directory and the program to just make a zip file exactly the same as the contents of that directory, with nothing else. Is that possible? – user2290362 Dec 15 '14 at 12:53
@user2290362 - yes, that's the bit that was unclear. See updated answer. – mhawke Dec 15 '14 at 14:08

Python zipfile whole path is in file

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