Lambda with one primitive parameter
With
var listOfInt=(1 to 100).toList
listOfInt.foldRight(0)((current,acc)=>current+acc)
you have a lambda function operating on two parameter.
Lambda with one parameter of type tuple
With
var listOfTuple=List((1,"a"),(2,"b"),(3," "))
listOfTuple.map(x => x._1.toString + x._2.toString)
you have a lambda function working on one parameter (of type Tuple2[Int, String]
)
Both works fine with type inference.
Partial lambda with one parameter
With
listOfTuple.map{case (x,y) => x.toString + y.toString}
you have a lambda function, working with one parameter (of type Tuple2[Int, String]
). This lambda function then uses Tuple2.unapply
internally to decompose the one parameter in multiple values. This still works fine with type inference. The case
is needed for the decomposition ("pattern matching") of the value.
This example is a little bit unintuitive, because unapply returns a Tuple as its result. In this special case there might indeed be a trick, so Scala uses the provided tuple directly. But I am not really aware of such a trick.
Update: Lambda function with currying
Indeed there is a trick. With
import Function.tupled
listOfTuple map tupled{(x,y) => x.toString + y.toString}
you can directly work with the tuple. But of course this is really a trick: You provide a function operating on two parameters and not with a tuple. tupled
then takes that function and changes it to a different function, operating on a tuple. This technique is also called uncurrying.
Remark:
The y.toString
is superfluous when y
is already a string. This is not considered good style. I leave it in for the sake of the example. You should omit it in real code.