jQuery Tablesorter - initial sort rows from array

Question

i'm trying to inital sort a table by it's row-numbers from an array/variable like

$list: row0=id2;row1=id0;row2=id1...

<table>
<tr id="0">...</tr>
<tr id="1">...</tr>
<tr id="2">...</tr>
</table>

How can i handle with tablesorter that the rows will be sorted like in $list?

thanks for any tipp or workaround :)

Use your list with sortlist param http://tablesorter.com/docs/example-option-sort-list.html — trainoasis, Dec 16 '14 at 10:26
thanks :) ... i've tried but i can't get the array used for sort :( — John Doe, Dec 17 '14 at 11:25

score 0 · Answer 1 · edited May 23 '17 at 12:24

0

This is a possible duplicate of: How to sort DOM elements while selecting in jQuery?

$('#myt tr').sort(function(a, b) {
  if (parseInt(a.id) > parseInt(b.id)) return 1;
  else return -1;
}).each(function() {
  $('#myt').append($(this));
});

td {
  border: 1px solid grey;
  padding: 10px;
}

<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script>
<table id='myt'>
  <tr id="8">
    <td>8</td>
  </tr>
  <tr id="1">
    <td>1</td>
  </tr>
  <tr id="21">
    <td>21</td>
  </tr>
  <tr id="5">
    <td>5</td>
  </tr>
</table>

edited May 23 '17 at 12:24

Community

1
1

answered Dec 16 '14 at 10:33

Ahmad

12,336
6
48
88

that's my array Array (1) 0 => "0=4;1=0;2=1;3=2;4=3" what i need is the following issue: 0=4; means id4 will become row 0 – John Doe Dec 17 '14 at 11:26
the array is build with var ordered_items = $.tableDnD.serialize('id'); – John Doe Dec 17 '14 at 11:28

score -1 · Answer 2 · answered Dec 17 '14 at 12:38

-1

maybe not what was originally intended but it's a workaround :)

var sortTable = [1,5,2,3,4];
$.each(sortTable, function(){
   $("table#productList").append($("#" + this));
 })

thanks for the responses and help!!

answered Dec 17 '14 at 12:38

John Doe

45
1
5

jQuery Tablesorter - initial sort rows from array

2 Answers2