ffmpeg not creating video from images

Question

I have read this Create Video using ffmpeg

Still I am not able to get it. I have written this shell command in PHP

echo $make_movie = "$ffmpeg -framerate 1/5 -i $folder_name/img%03d.png -c:v libx264 -r 25 -pix_fmt yuv420p $folder_name/output.mp4";

This gives output

ffmpeg\bin\ffmpeg.exe -framerate 1/5 -i ankit/img%03d.png -c:v libx264 -r 25 -pix_fmt yuv420p ankit/output.mp4

if(shell_exec($make_movie)){
    echo "<br />Movie Created..<br />";
}
else{
    echo "<br />Movie Creation Error..<br />";
}

The Output is Movie Creation Error that means the Shell Command is not executing?

Questions:

What is wrong?
For future use, any debugging methods for this?

I ran the same command on cmd and it made the video..!!!

Remove the echo statement from variable assignment. I.e Change `echo $make_move=` to `$make_movie=` and then run `exec($make_movie)` — 에이바바, Dec 16 '14 at 19:51
it means that shell_exec return a NULL or empty string, signifying no output or error. DOn't use shell_exec. use `exec()` instead, which can capture all of the output, and give you an exit code as well. — Marc B, Dec 16 '14 at 19:53
@MarcB, I increased the maximum execution time and restarted apache, it worked! My code was working already... — Knight Rider, Dec 16 '14 at 20:02

score 1 · Answer 1 · answered Dec 16 '14 at 19:55

shell_exec is pretty useless when it comes to figuring out why your command failed. use exec() instead:

$last_line = exec($make_movie, $all_output, $exit_code);
var_dump($exit_code);

You'll have to look at ffmpeg's docs to determine what the exit code means

ffmpeg not creating video from images

1 Answers1