Why cout gives me a result in reverse order?

Question

I'm newbie in c++ and i am doing some exercises.

I have a code

#include <cstdlib>
#include <iostream>

using namespace std;
int main(void) {
int i=0;
int a,b,c;
a = i++;
b = i++;
c = i++;

cout << a << b << c;
return 0;
}

and, whe I run it, the result is: 012

But when I run it without variables a, b and c, like in following code

#include <cstdlib>
#include <iostream>

using namespace std;
int main(void) {
int i=0;
cout << i++ << i++ << i++;
return 0;
}

I get result in reverse order: 210

Why is this happening? I think it should be again 012 (I am using NetBeans)

http://stackoverflow.com/questions/7718508/order-of-evaluation-of-arguments-using-stdcout — ford, Dec 17 '14 at 14:07

score 1 · Answer 1 · answered Dec 17 '14 at 14:08

1

You are violating the rules of the language that has multiple increment and decrement in the same expression or as different arguments to the same call as undefined.

answered Dec 17 '14 at 14:08

George Houpis

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Why cout gives me a result in reverse order?

1 Answers1