Javascript Decimal Subtract

Question

I am trying this code on the Firefox console, and I don't know how to get the correct answer(0.11). I would like to understand why this code doesn't work as I expected. Can someone help me understand. Thanks!

  var a = "12,25";
  var b = "12,14";

  console.log("A: " + a);
  console.log("B: " + b);

  var parsedA = parseFloat(a.replace(',', '.'));
  var parsedB = parseFloat(b.replace(',', '.'));

  console.log('Parsed A: ' + parsedA);
  console.log('Parsed B: ' + parsedB);

  console.log("Dif Parsed Float: " + (parsedA - parsedB));

  var numberA = Number(a.replace(',', '.'));
  var numberB = Number(b.replace(',', '.'));

  console.log('Number A: ' + numberA);
  console.log('Number B: ' + numberB);

  console.log("Dif Number: " + (parsedA - parsedB));

Just do `(parsedA - parsedB).toFixed(2)` – David Sherret Dec 17 '14 at 19:04 — David Sherret, Dec 17 '14 at 19:04
Yes, it's that simple. Thanks! – voidmain Dec 17 '14 at 19:06 — voidmain, Dec 17 '14 at 19:06

score 0 · Accepted Answer · answered Dec 17 '14 at 19:06

Just use toFixed(2) for your result

  var a = "12,25";
  var b = "12,14";

  console.log("A: " + a);
  console.log("B: " + b);

  var parsedA = parseFloat(a.replace(',', '.'));
  var parsedB = parseFloat(b.replace(',', '.'));

  console.log('Parsed A: ' + parsedA);
  console.log('Parsed B: ' + parsedB);

  console.log("Dif Parsed Float: " + (parsedA - parsedB));

  var numberA = Number(a.replace(',', '.'));
  var numberB = Number(b.replace(',', '.'));

  console.log('Number A: ' + numberA);
  console.log('Number B: ' + numberB);

  console.log("Dif Number: " + (parsedA - parsedB).toFixed(2)); //<<< here

Javascript Decimal Subtract

1 Answers1