The most pythonic way to slice a Python list every 100 elements

Question

I have a list contains many elements. I want to slice it every 100 elements to a list of several lists.

For example:

>>> a = range(256)
>>> b = slice(a, 100)

b should then be [[0,1,2,...99],[100,101,102,...199],[200,201,...,255]].

What's the most pythonic and elegent way to do that?

This is, however, a dup of literally dozens of questions. I can't find a canonical one that gives both good answers and compares and contrasts the two, so I'll pick one arbitrarily… — abarnert, Dec 18 '14 at 04:11

score 18 · Accepted Answer · answered Dec 18 '14 at 03:56

18

This should do the trick:

[a[i:i+100] for i in range(0, len(a), 100)]

range takes an optional third step argument, so range(0, n, 100) will be 0, 100, 200, ....

answered Dec 18 '14 at 03:56

tckmn

1 Answers1