Increment value not incremnting on return

Question

this is what i am doing. I am incrementing php var through a function like:

<?php $j=1; ?>

jQuery('.mysubmitbuttin').click(function(){

increment();

});

function increment()
{
    var inc = '<?php echo $j=$j+1; ?>';
    alert(inc);
    return inc;
}

the alert inc showing 2 everytime. php var $j is not incrementing the value. why is it so?

Jack, that is not a php function, that is a JS function. Anyway, then I've read the post you suggest, and realised, that was a good to close. Sorry, I can not cancel my reopen request. — vaso123, Dec 18 '14 at 12:03
@lolka_bolka Yeah, it's a JavaScript function trying to call a piece of PHP code; same rule applies :) — Ja͢ck, Dec 18 '14 at 12:09

score 0 · Answer 1 · answered Dec 18 '14 at 11:57

0

php-code is only executed once on the SERVER ! before you get the DOM-Element

answered Dec 18 '14 at 11:57

Alexis Peters

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Increment value not incremnting on return

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