Is Callback become closures?

Question

function fn(args){
    var a= 'something';
    doSomething('dummy',function(){

    });
}

fn();

In this code, is anonymous callback become closure or just exit after execution? If it become become a closure, how can i get back memory because it always has access to fn's activation object.

score 1 · Accepted Answer · edited May 23 '17 at 10:26

1

It will only be a closure if the lambda uses the enclosing functions'(fn) local variables or parameter, e.g. a or args.

Re: Memory recovery - Don't worry about it* - the GC will know when references are no longer reachable and collect them (whether they are used in closures or not). See also here.

_{* Don't worry too much}

edited May 23 '17 at 10:26

Community

1
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answered Dec 19 '14 at 21:52

StuartLC

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If i use `fn` local variables or `arguments`, it will be closure.So, i m creating closure every time when i call `fn` & how can I clean the scope after callback was execute to get back memory. – Thant Sin Aung Dec 19 '14 at 22:07

Is Callback become closures?

1 Answers1