Sending Email attachment (.txt file) using Python 2.7 (smtplib)

Question

So I'm trying to send a .txt file as an attachment and I can't find the right code to work. Here is my code:

import pythoncom
import win32gui
import win32console
import smtplib
from email.mime.multipart import MIMEMultipart
from email.mime.text import MIMEText


fromaddr = 'zover1@gmail.com'
toaddrs = 'zover2@gmail.com'
msg = "contrl text file"
username = 'zover1@gmail.com'
password= 'xxxxxxxxxxxx'
server = smtplib.SMTP('smtp.gmail.com:587')
f = file("d:/control.txt")
attachment = MIMEText(f.read())
attachment.add_header('Content-Disposition', 'attachment', filename="d:/control.txt")
msg.attach(attachment)
server.ehlo()
server.starttls()
server.login(username, password)
server.sendmail(fromaddr, toaddrs, msg)
server.quit()

And when I run the module I get this error:

Traceback (most recent call last):
  File "C:\Python278\emailonlytester.pyw", line 19, in <module>
msg.attach(attachment)
AttributeError: 'str' object has no attribute 'attach'

Any help would be much appreciated.

Did you check [How to send Email Attachments with python](http://stackoverflow.com/questions/3362600/how-to-send-email-attachments-with-python)? — fredtantini, Dec 23 '14 at 13:09
Edited the question to hide the OP's password. @Zover Lul, I recommend you to change your password if it was an authentic one. :) — ρss, Dec 23 '14 at 13:31

Oscar · Answer 1 · 2014-12-23T13:25:18.153

1

You can try this to send an attached file with python:

msg = MIMEMultipart()
msg['From'] = 'your adress'
msg['To'] = 'someone'
msg['Date'] = formatdate(localtime=True)
msg['Subject'] = 'a random subject'
msg.attach(MIMEText("some text"))
file = 'd:/control.txt'
attachment = MIMEBase('application', 'octet-stream')
attachment.set_payload(open(file,'rb').read())
encoders.encode_base64(attachment)
attachment.add_header('Content-Disposition', 'attachment; filename="%s"' % os.path.basename(file))
msg.attach(attachment)

This is the part for the creation of the Email, not the sending.

edited Dec 23 '14 at 13:25

answered Dec 23 '14 at 13:18

Oscar

231
4
17

I pasted the above code but I'm getting an error like this: Traceback (most recent call last): File "C:\Python278\emailonlytester.pyw", line 26, in server.ehlo() NameError: name 'server' is not defined don't see how its not defined, i have smtplib imported. It worked when I wasn't sending an attachment – Zover Lul Dec 23 '14 at 14:18
The code I provided does not contain any reference to `server`, can you show me how you implemented this piece of code in yours ? – Oscar Dec 23 '14 at 15:00
file = 'd:/control.txt' attachment = MIMEBase('application', 'octet-stream') attachment.set_payload(open(file,'rb').read()) attachment.add_header('Content-Disposition', 'attachment; filename="%s"' % os.path.basename(file)) msg.attach(attachment) username = 'zover.lul@gmail.com' password= 'battlefield34' msg = "contrl text file" server.ehlo() server.starttls() server.login(username, password) server.sendmail(fromaddr, toaddrs, msg) server.quit() – Zover Lul Dec 23 '14 at 18:58
Well from what you gave me here, there is no server define, if this is all the code you are using, no wonder it is not working. You should try to reuse some old parts of the code you gave us in the first place. – Oscar Dec 24 '14 at 09:06

score 0 · Answer 2 · answered Dec 23 '14 at 13:21

0

The error is clearly stating the reason. msg is a string in your case. You may want to do the following instead:

msg = MIMEMultipart()

Docs are here.

answered Dec 23 '14 at 13:21

ρss

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8
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73

Sending Email attachment (.txt file) using Python 2.7 (smtplib)

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