15

I wonder how to get the element of lsmobj from lsmeans package in R.

require(lsmeans)
fiber.lm <- lm(strength ~ diameter + machine, data = fiber)
fiber.lsm <- lsmeans (fiber.lm, "machine")
fiber.lsm
machine   lsmean        SE df lower.CL upper.CL
 A       40.38241 0.7236252 11 38.78972 41.97510
 B       41.41922 0.7444169 11 39.78077 43.05767
 C       38.79836 0.7878785 11 37.06426 40.53247

Confidence level used: 0.95 


str(fiber.lsm)
'lsmobj' object with variables:
    machine = A, B, C

I want extract lsmeans and SE columns of fiber.lsm.

halfer
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MYaseen208
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1 Answers1

22

fiber.lsm is an S4 object that cannot be subsetted. But you can use the summary of the object. It returns a data frame of the model results.

s <- summary(fiber.lsm)

class(s)
# [1] "summary.ref.grid" "data.frame"   

s[c("lsmean", "SE")]
#   lsmean        SE
# 40.38241 0.7236252
# 41.41922 0.7444169
# 38.79836 0.7878785

c(s[c("lsmean", "SE")])
# $lsmean
# [1] 40.38241 41.41922 38.79836
#
# $SE
# [1] 0.7236252 0.7444169 0.7878785
Rich Scriven
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