I am using the follwoing regular expression
(".+@.+\\.[a-z]+")
Bit it accepts #@#.com as a valid email. What's the pattern I should use?
I am using the follwoing regular expression
(".+@.+\\.[a-z]+")
Bit it accepts #@#.com as a valid email. What's the pattern I should use?
You should use apache-commons email validator. You can get the jar file from here.
Here is a simple example of how to use it:
import org.apache.commons.validator.routines.EmailValidator;
boolean isValidEmail = EmailValidator.getInstance().isValid(emailAddress);
Here's a web page that explains that better than I can: http://www.regular-expressions.info/email.html (EDIT: that appears to be a bit out of date since it refers to RFC 2822, which has been superseded by RFC 5322)
And another with an interesting take on the problem of validation: http://www.markussipila.info/pub/emailvalidator.php
Generally the best strategy for validating an email address is to just try sending mail to it.
If somebody wants to enter non-existent email address he'll do it whatever format validation you choose.
The only way to check that user owns email he entered is to send confirmation (or activation) link to that address and ask user to click it.
So don't try to make life of your users harder. Checking for presence of @
is good enough.
I usually use the following one:
([a-zA-Z0-9]+(?:[._+-][a-zA-Z0-9]+)*)@([a-zA-Z0-9]+(?:[.-][a-zA-Z0-9]+)*[.][a-zA-Z]{2,})
import java.util.regex.*;
class ValidateEmailPhone{
public static void main(String args[]){
//phone no validation starts with 9 and of 10 digit
System.out.println(Pattern.matches("[9]{1}[0-9]{9}", "9999999999"));
//email validation
System.out.println(Pattern.matches("[a-zA-Z0-9]{1,}[@]{1}[a-z]{5,}[.]{1}+[a-z]{3}", "abcd@gmail.com"));
}
}
This is my regex for email validation:
(([a-zA-Z0-9]+)([\.\-_]?)([a-zA-Z0-9]+)([\.\-_]?)([a-zA-Z0-9]+)?)(@)([a-zA-Z]+.[A-Za-z]+\.?([a-zA-Z0-9]+)\.?([a-zA-Z0-9]+))
For username it allows ".", "_", "-" for separators. After "@" allows only "." and "-". Can be easy modified for more words.