How to make the 'setInterval' run in start moment

Question

Below code, will delay 10 second then execute the function A and B first time.

setInterval(function () {
    A();
    B();
}, 10000);

I wanna execute A and B at the program run at the same time. Like,

A();
B();
setInterval(function () {
    A();
    B();
}, 10000);

There is no better way to do it?

Thanks all.

you want them to run once when the program loads? what does it mean at the same time? — Lior Raz, Dec 24 '14 at 01:22
make the function execute them, then setTimeout(self,10000) in the tail — dandavis, Dec 24 '14 at 01:29

score 0 · Answer 1 · answered Dec 24 '14 at 01:54

0

Use a named function

var fnc = function(){
 A(); B();
};
window.setInterval(fnc,10000);
fnc();

Or use setTimeout

(function x(){ A(); B(); window.setTimeout(x, 10000);}())

answered Dec 24 '14 at 01:54

epascarello

1 Answers1