How to calculate Time Between Day one and Day two (Python)

Question

 from datetime import datetime

 FMT = '%H%M'
 rate1 = 35.34 
 Midnight = "0000"

signOnSun1 = raw_input("What time did you sign on Sunday: ");
signOffSun1 = raw_input("What time did you sign off Sunday: ");

totalShift = (datetime.strptime(signOffSun1, FMT) - datetime.strptime (signOnSun1,   FMT))

midnightToSignOff = (datetime.strptime(signOffSun1, FMT) - datetime.strptime (Midnight, FMT))
midnightToSignOff = diff.total_seconds()/60.0/60

basically this is what i have. if i sign on at 1800 and sign off that night at 0200 i can't return a proper answer of 8 8 hours

Can you give us a much simple bit of code showing what you want to do? One without tons of unnecessary constants and Tkinter and user input? — John Zwinck, Dec 25 '14 at 03:55
Use `datetime` (`datetime.timedelta` in specific) in order to find time differences. — Nir Alfasi, Dec 25 '14 at 03:57
shouldn't it return 2 hours, midnight to 0200? or do you want the total time between sign on and sign off? — Hesham Attia, Dec 25 '14 at 04:12

score 0 · Answer 1 · answered Dec 25 '14 at 04:34

The problem is the program doesn't know that the shift ended on the next day. To account for that, you can check if the sign on time is later than the sign off time, if that's the case, add a day to the sign off time.

from datetime import datetime, timedelta

FMT = '%H%M'
sign_on_time_str = raw_input("What time did you sign on Sunday: ");
sign_off_time_str = raw_input("What time did you sign off Sunday: ");
sign_on_time = datetime.strptime(sign_on_time_str, FMT)
sign_off_time = datetime.strptime(sign_off_time_str, FMT)

if sign_on_time > sign_off_time:
    sign_off_time += timedelta(days=1)

total_shift = sign_off_time - sign_on_time
print total_shift.total_seconds() / 60 / 60

How to calculate Time Between Day one and Day two (Python)

1 Answers1