Jasmine have createSpy() return mock object

Question

I'm trying to mock up a response object, and it looks something like this:

var res = {
  status: jasmine.createSpy().andReturn(this),
  send: jasmine.createSpy().andReturn(this)
}

This returns the jasmine object. I'd really like to return the original res variable containing the mocked functions. Is that possible? I'm mainly implementing this to unit test functions containing res.status().send(), which is proving to be difficult.

Possible duplicate of [jasmine: spyOn(obj, 'method').andCallFake or and.callFake?](https://stackoverflow.com/questions/22041745/jasmine-spyonobj-method-andcallfake-or-and-callfake) — AncientSwordRage, Nov 14 '18 at 10:24

score 34 · Accepted Answer · edited Jan 06 '20 at 13:29

34

The answer here is actually pretty quick. Calling andReturn() will give you jasmine as 'this'. But, if you write andCallFake(), that function considers the mocked object to be this. Solution looks like so:

status: jasmine.createSpy().and.callFake(function(msg) { return this });

edited Jan 06 '20 at 13:29

Francesco Borzi

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answered Dec 28 '14 at 21:54

ritmatter

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Asked and answered. +2 internets for you. – Michael Blackburn Mar 17 '15 at 03:03
20

In Jasmine 2.4 it is now `.and.callFake(function() {})` – FirstVertex Jul 18 '16 at 20:23

score 10 · Answer 2 · answered Dec 02 '16 at 14:32

10

this works for me:

const res = {
  status: jasmine.createSpy('status').and.callFake(() => res),
  send: jasmine.createSpy('send').and.callFake(() => res),
};

answered Dec 02 '16 at 14:32

Olivier Torres

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Jasmine have createSpy() return mock object

2 Answers2