Understand JS .match() work

Question

Hi i have next string and regexp:

"Hello many 2014 (12) and another (88)".match(/\((\d+)\)/g)

Why return value is ["(12)", "(88)"] instead of [12, 88] ? I need a second option.

Fix the title of your post. The regexp is working fine. What is not working is your understanding of how `match` works. — , Dec 29 '14 at 09:54
`.match()` returns all the matches of the entire regexp, not just the capture group. — Barmar, Dec 29 '14 at 10:00

score -1 · Accepted Answer · answered Dec 29 '14 at 09:49

-1

\d+(?=\))

You can try this.This should work for you.

If you have strings like abc (def 234) (45) Then use \((\d+)\) and grab group 1.

answered Dec 29 '14 at 09:49

vks

3

It will not work correctly for the input string `abc (def 234) (45)` – nhahtdh Dec 29 '14 at 09:50
1

OP's intention seems to be to extract 45 out of the example string I gave above and leave 234 alone. – nhahtdh Dec 29 '14 at 09:52
It is doesn't work for me ["(12", "(88"] = "Hello many 2014 (12) and another (88)".match(/\(\d+(?=\))/g) – Ilya Manyahin Dec 29 '14 at 10:02
1

@IlyaManyahin `\d+(?=\))` you have use soething different – vks Dec 29 '14 at 10:03

1 Answers1