App crash when I submit a new post to Parse

Question

This is the only Place my app crashes and one of the more important features

The LogCat tells me:

java.lang.IllegalArgumentException: You must create this type of ParseObject using ParseObject.create() or the proper subclass. at line 37.

I tried the ParseObject.create() however that just caused more problems (I may have done it incorrectly). How Should I code this?

Here is my newPost class:

public class newPost extends Activity {

private Button addButton;

private TextView postView;

@Override
public void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.newpost);

    postView = ((EditText) findViewById(R.id.postView));

    addButton = ((Button) findViewById(R.id.addButton));
    addButton.setOnClickListener(new View.OnClickListener() {

        @Override
        public void onClick(View v) {
            //line 37 Below
            ParseObject post = new ParseObject("Posts");
            post.put("content", postView);
            post.saveInBackground(new SaveCallback () {

                @Override
                public void done(ParseException e) {
                    if (e == null) {
                        setResult(RESULT_OK);
                        finish();
                    } else {
                        Toast.makeText(getApplicationContext(),
                                "Error saving: " + e.getMessage(),
                                Toast.LENGTH_SHORT)
                                .show();
                    }
                }

            });

        }
    });



}

score 5 · Accepted Answer · answered Jan 01 '15 at 02:32

5

Replace this line

ParseObject post = new ParseObject("Posts");

with this

ParseObject post = ParseObject.create("Posts");

answered Jan 01 '15 at 02:32

Greg Ennis

14,917
2
69
74

@Johnny you're right, this should not be needed. See my answer. I had the same problem. – Loolooii Aug 24 '16 at 20:43
API change? So weird. – Martin Erlic Feb 20 '17 at 18:46
i am facing same issue when i update data. if i create a new Parse Object than exception arrive is signUp first but i already login in same user – Mehul Tank May 25 '17 at 10:57

chrisbiz155 · Answer 2 · 2015-08-20T18:59:11.263

3

In my case I had to remove the '@ParseClassName' annotation in my model class. My understanding is that if I have a parse model class 'Posts' and I call 'registerSubclass(yourclassname)' in Application, then all I need is

Post obj = new Post();

edited Aug 20 '15 at 18:59

answered Aug 20 '15 at 18:48

chrisbiz155

41
2
6

score 3 · Answer 3 · answered Dec 27 '16 at 22:14

3

Ensure that you've added the below line in the Application.java class where Parse is initialised

ParseObject.registerSubclass(Message.class);

answered Dec 27 '16 at 22:14

AnupamChugh

1,779
1
25
36

score 1 · Answer 4 · answered Aug 24 '16 at 20:42

1

You probably made a mistake in initialising Parse in your Application class. Or forgot to put android:name=".YourApplicationClass" in your Manifest file.

answered Aug 24 '16 at 20:42

Loolooii

8,588
14
66
90

score 0 · Answer 5 · answered May 19 '17 at 10:04

I got this error because I forgot to register my parse class as a subclass in my application extension:

public class App extends Application
{
    @Override
    public void onCreate()
    {
        super.onCreate();

        App application = this;

        ParseObject.registerSubclass(Posts.class); // <-- This is what you need

        Parse.enableLocalDatastore(this);
        Parse.initialize(new Parse.Configuration.Builder(getApplicationContext())
                                 .applicationId(EnvironmentConfig.appID)
                                 .server(EnvironmentConfig.serverName)
                                 .enableLocalDataStore()
                                 .build());

        ParseInstallation.getCurrentInstallation().saveInBackground();
    }
}

App crash when I submit a new post to Parse

5 Answers5

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