I have a python date formatted like this 1418572798.498 within a string.
In Java the dates are formatted like this 1418572798498.
How to convert this string to Java date? Is there any third party library to use for the conversion?
Asked
Active
Viewed 3,104 times
0
-
1That's not "python time", btw. That's Unix/POSIX time (seconds since 1970-01-01 00:00:00). "Java time" is the same but in microseconds :-P – Ricardo Cárdenes Jan 02 '15 at 16:33
-
You just turn the string into a float, and then multiply that number by 1000 – Anthony Pham Jan 02 '15 at 16:33
-
1@RicardoCárdenes No, not microseconds. The java.util.Date class uses milliseconds since epoch, as does the Joda-Time library. The new java.time package in Java 8 (JSR 310) uses nanoseconds since epoch. Some databases such as Postgres use microseconds since epoch. See [this diagram](http://i.stack.imgur.com/cpOL8.png). – Basil Bourque Jan 02 '15 at 16:46
-
Sorry, miliseconds. That was a brainfart. – Ricardo Cárdenes Jan 02 '15 at 16:47
-
@davidzhao Please search StackOveflow before posting. This question has been addressed *many* times. – Basil Bourque Jan 02 '15 at 16:48
-
@BasilBourque, i konw that question, but they are different. i just want to konw is there any better ways. thans for your wanning. – dwzhao Jan 02 '15 at 16:54
-
@davidzhao You should explain in your Question how it is different from near duplicates. I don't see a difference yet. Same answer for your Question and the many duplicates: Convert string to a number, multiply by a thousand to get a long/Long, feed to constructor of java.util.Date (or better, Joda-Time). – Basil Bourque Jan 02 '15 at 16:58
3 Answers
5
Try something like:
String number = "1418572798.498";
long d = Long.parseLong(number.replace(".", ""));
System.out.println(d + " " + new Date(d));
Output:
1418572798498 Sun Dec 14 21:29:58 IST 2014
SMA
- 36,381
- 8
- 49
- 73
2
Do this:
float time = Float.parseFloat(string);
long actual_time = (int)(time*1000);
Date d = new Date(actual_time);
SalmonKiller
- 2,183
- 4
- 27
- 56
-
Integer.parseInt will throw a NumberFormatException for the string given by the OP. I think a float or double should be used... – Diego Jan 02 '15 at 16:42
-
