readlines() without EOL at the of the lines

Question

I want to get a lot of usernames from file - each line is one username. Currently I use this code:

lista = []
z = open("usrnames.txt")
lista = z.readlines()

But then the results, which are saved in list are:

['username1\n', 'username2\n', 'username3\n']

I do not want to have EOLs... I except this result:

['username1', 'username2', 'username3']

How can I do that? I read documentation of this function, and didn't find any argument, which can disable putting EOLs...

fredtantini · Accepted Answer · 2015-01-05T15:20:11.580

6

You could either use list comprehension with strip:

lista = [line.strip() for line in z.readlines()]

or simply, as suggested by @Matthias:

lista = [line.strip() for line in z]

or use splitlines:

lista = z.read().splitlines()

edited Jan 05 '15 at 15:20

answered Jan 05 '15 at 15:10

fredtantini

1

And now we should get rid of the `readlines` call: `lista = [line.strip() for line in z]` – Matthias Jan 05 '15 at 15:19
1

Ok I like `splitlines()` and will use it ! THANKS! – TN888 Jan 05 '15 at 15:21

1 Answers1