Python: call a method with the name stored in a variable

Question

I am writing a python program where in I have included another python file.

The python file included has a method which I want to invoke from the calling script.

Like:

#!/usr/bin/python    
include script1

method = sys.argv[1]     # values may be - create or destroy

if method == "create":
    script1.create()
elif method == "destroy":
    script1.destroy()

Now, what I want is,

#!/usr/bin/python    
include script1

method = sys.argv[1]       # values may be - create or destroy

script1.method()

and, it should use the value inside the variable method instead of trying to call the module called method.

@KarolyHorvath it was only supposed to be pseudo for understanding... but anyways, ill correct it :) — user3762302, Jan 10 '15 at 10:21
Possible duplicate of [Call a Python method by name](https://stackoverflow.com/questions/3521715/call-a-python-method-by-name) — Aran-Fey, Jan 23 '18 at 18:25

score 2 · Accepted Answer · answered Jan 10 '15 at 10:10

2

You can use getattr.

method= sys.argv[1]
getattr(script1, method)()

answered Jan 10 '15 at 10:10

Aran-Fey

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score 0 · Answer 2 · answered Jan 10 '15 at 10:12

0

To call functions from script1, you could turn it into a module.

script1.py:

def create():
   pass

def destroy():
   pass

script2.py:

import script1

script1.create()
script1.destroy()

answered Jan 10 '15 at 10:12

NPE

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Python: call a method with the name stored in a variable

2 Answers2