How to loop for a fixed number of iterations?

Question

Is there any way of making a for loop iterate a fixed number of times, even though the right side of the interval might be increasing ? I want to do this without declaring an additional variable to use as a copy of the initial inc. For example:

for (i = 0; i < inc; i++)
{
  if (condition) 
  {
     inc++;
  }
}

I am pretty sure that if inc increases, the for will execute more than inc - 1 times. How can I iterate exactly inc times, without using a copy of inc ?

You aren't looping a fixed number of iterations so you shouldn't use a for loop, should be a while. I'd tear you a new one in code review even if you got this to work somehow.... — Tony Hopkinson, Jan 10 '15 at 12:00

score 2 · Accepted Answer · answered Jan 10 '15 at 11:58

2

for (i = inc; i > 0; i--) {
    if (condition) {
        inc++;
    }
}

This would work since you only assign inc once.

answered Jan 10 '15 at 11:58

Floris Velleman

4,848
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score 0 · Answer 2 · answered Jan 10 '15 at 12:08

0

I think you are possibly looking for a 'range', you don't say what language its for but in python something like:

 inc = 2
 for i in range[0:10]:
      if i > inc:
           inc=inc+1
      print inc

answered Jan 10 '15 at 12:08

user3062260

1,584
4
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for java see here: http://stackoverflow.com/questions/3790142/java-equivalent-of-pythons-rangeint-int – user3062260 Jan 10 '15 at 12:11

How to loop for a fixed number of iterations?

2 Answers2