why method varargs must be in separate block in java?

Question

Why method varargs must be in separate from main method body? Below code is correct, but why can't I put varargs method declaration in the main method body?

public class TryVariableArgumentList {

    public static void main(String[] args) {
        x("first","second");

        public static void x(String... list) {
            for (String y : list)
                System.out.println(y);
        }
    }
}

possible duplicate of [Why doesn't Java's main use a variable length argument list?](http://stackoverflow.com/questions/2201696/why-doesnt-javas-main-use-a-variable-length-argument-list) — Thomas Jungblut, Jan 11 '15 at 12:41

score 4 · Accepted Answer · edited Jan 11 '15 at 13:00

4

the method

public static void main(String... args) {
    //code
}

is also perfectly legal

The problem with the code is Method declaration inside a method itself is not allowed in Java

Compilable code has to be like this

class TryVariableArgumentList {
    public static void main(String[] args) {
        x("first","second");
    }

    public static void x(String... list) {
        for(String y : list)
            System.out.println(y);
    }
}

I think you need to post what you read,because maybe you have interpreted something incorrectly

Hope this helps!

edited Jan 11 '15 at 13:00

Mark Rotteveel

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answered Jan 11 '15 at 12:42

Vihar

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thank you , i changed my code ,can you tell me why it's not compiled? – Jan 11 '15 at 12:49
1

Method inside a method is not allowed in Java – Vihar Jan 11 '15 at 12:50
Edited my answer tooo – Vihar Jan 11 '15 at 12:52

score 0 · Answer 2 · answered Jan 11 '15 at 12:52

0

Your method x is declared in method main. This is not legal. Declare x outside of main.

answered Jan 11 '15 at 12:52

Koray Tugay

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why method varargs must be in separate block in java?

2 Answers2