1

I'm having the pandas DataFrame 'test_df':

email                      my_list
email1@email1.com          [1,9,3,5]
email2@email2.com          [6,3,3,15]
email3@email3.com          [7,7,2,5]
email4@email4.com          [5,5,5,5]

How can I have this following DataFrame (take the first 2 elem of 'my_list'):

email                      col1             col2             
email1@email1.com          1                9        
email2@email2.com          6                3
email3@email3.com          7                7
email4@email4.com          5                5           

I tried:

test_df['col1'] = test_df['my_list'][0]
test_df['col2'] = test_df['my_list'][1]

But it's not working

MattDMo
  • 100,794
  • 21
  • 241
  • 231
woshitom
  • 4,811
  • 8
  • 38
  • 62

1 Answers1

3

I asked a related question here, although I wanted to go a bit beyond expanding the lists into columns so the answers are more complicated than what you need. In your case, you can just do:

# Using my own example data since it's a bit tough to copy-paste
# a printed table and have the lists show up as lists
df = pd.DataFrame({'email': ['email1@eg.com', 'email2@eg.com'], 
                   'lists': [[1, 9, 3, 5], [6, 3, 3, 15]]})
df
Out[14]: 
           email          lists
0  email1@eg.com   [1, 9, 3, 5]
1  email2@eg.com  [6, 3, 3, 15]

objs = [df, pd.DataFrame(df['lists'].tolist()).iloc[:, :2]]
pd.concat(objs, axis=1).drop('lists', axis=1)
Out[13]: 
           email  0  1
0  email1@eg.com  1  9
1  email2@eg.com  6  3
Community
  • 1
  • 1
Marius
  • 58,213
  • 16
  • 107
  • 105