How do I get a number with two digits after the decimal using double type numbers in C#?

Question

I'm coding a simple calculator, and it needs to be displaying 2 digits after the decimal, but I can't figure it out. The rest of the program works perfectly, and so does the quotient button, but it's just displaying too many digits after the decimal. Here's what I have:

private double _leftop = 0;
private double _rightop = 0;
private double _quotient = 0;

    private void BtnQuotient_Click(object sender, EventArgs e)
    {
        if (Double.TryParse(TxtLeftOperand.Text, out _leftop) == true &&     Double.TryParse(TxtRightOperand.Text, out _rightop) == true)
        {
            _quotient = _leftop / _rightop;
            TxtResult.Text = Convert.ToString(_quotient);
        }
        else
        {
            TxtResult.Text = "Error";
        }
    }

Do you want to _display_ with two digits, or convert to two digits? The former you can use a `Format` on the output to a string, the latter as was posted as answer below, you can use `Math.Round()`. — Jane S, Jan 13 '15 at 02:47

score 0 · Accepted Answer · edited Jan 13 '15 at 02:48

0

TxtResult.Text = (Math.Round(_quotient, 2)).ToString();

edited Jan 13 '15 at 02:48

Abhishek

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answered Jan 13 '15 at 02:46

Shahar

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score 0 · Answer 2 · answered Jan 13 '15 at 02:46

0

Use Math.Round() method.

Math.Round(value, numOfDigits);

answered Jan 13 '15 at 02:46

Abhishek

2,925
4
34
59

How do I get a number with two digits after the decimal using double type numbers in C#?

2 Answers2