Java casting negative Integer to Double gives wrong result

Question

I'm trying to cast an Integer to Double but Java is giving me wrong results, i believe due to overflow.

Integer ii = -123456789;
Double dd = ii.DoubleValue();
System.out.println(dd);

I am expecting to receive -123456789.0, but instead i am getting -1.23456789E8.

Is there a way to get rid of the decimals to gain a little range in the integer part? Or another data type with bigger range?

PS. Im converting code from another language that allows this with the same number of variable bytes.

Define _wrong_. What is the difference between those _numbers_? — Sotirios Delimanolis, Jan 15 '15 at 02:43
Well, visually. I expect the decimal point to be printed in the correct position. I cant print it like this in invoices. — Brian, Jan 15 '15 at 02:47
You're actually casting to `float`, which is not a good idea. — SLaks, Jan 15 '15 at 02:48
Are these numbers [representing currency](http://stackoverflow.com/questions/3730019/why-not-use-double-or-float-to-represent-currency)? — Sotirios Delimanolis, Jan 15 '15 at 02:48
I hope you aren't using floating types to store currency amounts... — John3136, Jan 15 '15 at 02:49
I started learning not long ago. Is there a specific way to do it? (specific like everything else in this language) — Brian, Jan 15 '15 at 02:52
I can't replicated your reported behavior. What version of Java are you running? — Elliott Frisch, Jan 15 '15 at 02:56
Elliott, i have no idea what version of Java i am using. But i followed Soltirios' link and that gave me a solution... thanks! — Brian, Jan 15 '15 at 03:00

score 2 · Accepted Answer · answered Jan 15 '15 at 02:58

2

Instead of double try with BigDecimal

Integer ii = -123456789;
BigDecimal dd = new BigDecimal(ii);
System.out.println(dd);

answered Jan 15 '15 at 02:58

Robert

1 Answers1