How do I get the name of the function that calls a method?

Question

Consider the next example:

 function Test(){
    Log();
 }
 function Log(){
   console.log('Name of the called function');
 }

How do I get the name of the function, in this case Test(), Into my Log function without parameters of corse.

Consider that this works on this way:

function Hello(){
Log(); //should return Hello
}
function Test(){
Log(); //should return Test
}
function World(){
Log(); //should return World
}

function Log(){
return NAME_OF_FUNCTION;
}

Thanks

UPDATE:

I can use arguments.callee.name to get the name, but, this doesnt work on strict mode and If I delete de strict mode and I try to use it I get the name of clousure function and not the name of the parent method.. for example:

var Log = (function(){

function info(message){
console.log(arguments.callee) //This print function info(message){
}

return {
info:info
}
})();

function Test(){

Log.info("Some Message");

}

This is wrong, I need the name of Test function, not the info function.

score 2 · Answer 1 · edited May 23 '17 at 12:27

2

You could use this inside your function's body:

arguments.callee.caller.toString()

check this snippet:

function Test(){
    Log();
}

function Log(){
    alert(arguments.callee.caller.toString());
}

Test();

Update

If strict mode is used the above will not work.

Please read this, to see that Alex K. mentioned below in his comments. I didn't know it.

edited May 23 '17 at 12:27

Community

1
1

answered Jan 15 '15 at 14:30

Christos

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Wouldn't they just want `Test` in this case? – Spencer Wieczorek Jan 15 '15 at 14:33
1

I don't agree with this answer. It appears that the user wants just `Test` and not the entire: `function Test(){ Log(); }`. – Spencer Wieczorek Jan 15 '15 at 14:47
@SpencerWieczorek this is not possible as I am aware of. – Christos Jan 15 '15 at 14:53
@SpencerWieczorec I'm only want the name of the function, the answer below make exactly what I want. (arguments.callee.caller.name), but I use stric mode. So, I can use it. – cmarrero01 Jan 15 '15 at 18:13

Exinferis · Answer 2 · 2015-01-15T14:39:34.740

2

This should do the job:

arguments.callee.caller.name

But careful: 'caller', 'callee', and ~~'arguments'~~ properties cannot be used in strict mode they are deprecated in ES5 and removed in strict mode.

edited Jan 15 '15 at 14:39

answered Jan 15 '15 at 14:31

Exinferis

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7
17

Careful: `arguments` is not deprecated. – Felix Kling Jan 15 '15 at 14:34
@SpencerWieczorek: nope – Felix Kling Jan 15 '15 at 14:36
You are right arguments of course isn't deprecated, while callee and caller are. – Exinferis Jan 15 '15 at 14:38
`Function.arguments` is depreciated, `arguments` is not – Alex K. Jan 15 '15 at 14:38
@SpencerWieczorek: the problem was that the answer claimed that `arguments` is deprecated while it isn't. – Felix Kling Jan 15 '15 at 14:39
I need to use the strict mode, so, I can use this example. There is another way?. – cmarrero01 Jan 15 '15 at 18:15
As far as I know, this ain't possible in strict mode. There seems to be some sort of a hack, but its V8 only: http://stackoverflow.com/questions/9777905/how-to-get-caller-from-strict-mode – Exinferis Jan 15 '15 at 20:37

How do I get the name of the function that calls a method?

2 Answers2