Datetime Delta - Extract the seconds from output (Python)

Question

I have this small piece of code that keeps track of the runtime of a script:

startTime = datetime.now()
time = datetime.now() - startTime
return time

The type of "time" is "datetime.timedelta" and the output is "0:00:13.084000". I'm interested only in the seconds (13).

How can I extract that piece of information?

what language is this? Edit: Guessing python, but correct it if I am wrong ;p — leppie, Jan 17 '15 at 07:04
The correct syntax is "seconds" (with an s at the end). It works now. — Benjamin, Jan 17 '15 at 07:42
do not subtruct naive datetime objects that represent local time. Local time is not linear or even monotonous. See [Find if 24 hrs have passed between datetimes - Python](http://stackoverflow.com/a/26313848/4279). — jfs, Jan 17 '15 at 15:04

score 1 · Accepted Answer · answered Jan 17 '15 at 07:38

1

Your object is a datetime.timedelta instance, so use time.seconds for the seconds field only, or time.total_seconds() for all the time duration, converted to seconds (They're different things)

answered Jan 17 '15 at 07:38

bakkal

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Datetime Delta - Extract the seconds from output (Python)

1 Answers1