Random websites button

Question

this one is pretty simple I guess but I just can't find the answer that would suit perfectly for my issue. I want to make a button that opens a random URL from a list I'll give him, let's say - google, youtube and facebook just for the example. This is my line of code that connects now only to google...:

- (IBAction)site:(id)sender {
    [[UIApplication sharedApplication] openURL:[NSURL URLWithString:@"http://google.com"]];
}

Can someone please advise me what to add to the code so it will randomly pick these other websites as well?

Have the urls stored in an array then you can use the `rand()` function by passing it the size of the array to get a random number of which you'll use to select the index you want from the array to get your url. Also have a look at using the method `canOpenURL:` in an if statement to make sure you can up it — Popeye, Jan 18 '15 at 21:20
Thanks @Popeye ! altho i'm kind of a beginner so I didn't really get any of that... :) — Tooky, Jan 18 '15 at 21:27
As a side note: Method names and variables should start with lowercase and Classes and Enums should should with Uppercase I have amended — Popeye, Jan 19 '15 at 08:17
@TheParamagneticCroissant Since the tag is no longer there as I removed it yesterday it doesn't really matter what they put in there title as long as it is descriptive so it was a wasted edited really, it would have been better if you provided a more descriptive title instead. Though I'm not going to add it back it. — Popeye, Jan 19 '15 at 08:18

score 1 · Answer 1 · edited Jan 19 '15 at 08:16

1

Like Popeye said, you can store the URLs into a NSArray and pick one of them randomly:

#include <stdlib.h>

- (IBAction)site:(id)sender {
    NSArray *urls = @[
        [NSURL URLWithString:@"http://www.google.com"],
        [NSURL URLWithString:@"http://www.facebook.com"],
        [NSURL URLWithString:@"http://www.twitter.com"]
    ];

    int index = arc4random_uniform(urls.count);
    NSURL *randomURL = urls[index];

    if ([[UIApplication sharedApplication] canOpenURL:randomURL])
        [[UIApplication sharedApplication] openURL:randomURL];
}

edited Jan 19 '15 at 08:16

Popeye

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answered Jan 18 '15 at 21:25

Gustavo Barbosa

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I was going to provide an answer this morning but there is no point since you already beat me to it by transforming my comment above into an answer +1 – Popeye Jan 19 '15 at 08:15

Random websites button

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