Split a list into a list of lists by condition

Question

Could somebody help me to split a list into a list of lists by element ('#')?

Input:

['1', '2','#','3','4','#','5']

Output:

[['1', '2'], ['3','4'], ['5']]

Sorry. They were so bad. – Konstantin Kuleshov Jan 19 '15 at 08:36 — Konstantin Kuleshov, Jan 19 '15 at 08:36

score 2 · Answer 1 · answered Jan 19 '15 at 08:31

2

input = ['1', '2','#','3','4','#','5']
s = ''.join(input).split('#')
r = []
for i in s:
    r.append(list(i))
output = r

answered Jan 19 '15 at 08:31

ljk321

16,242
7
48
60

Can you add some explanation to your answer? – Alex Char Jan 19 '15 at 08:58
@AlexChar This is basically the same as zoosuck's answer above. First combine all the character in the list into a string, then split it using '#' as seperator. Now the list is ['12', '34', '5']. Then split all the strings back to list. – ljk321 Jan 19 '15 at 10:53

score 2 · Answer 2 · answered Jan 19 '15 at 08:31

2

Use string join and split method:

alist=  ['1', '2','#','3','4','#','5']
as_string = ' '.join(alist).split('#')
as_string_list = [i.strip().split(' ') for i in as_string]
print as_string_list

answered Jan 19 '15 at 08:31

lqhcpsgbl

3,694
3
21
30

score 1 · Answer 3 · edited May 23 '17 at 11:56

1

Here is your answer:

[list(x[1]) for x in itertools.groupby(myList, lambda x: x=='#') if not x[0]]

This question is a duplicate of Make Python Sublists from a list using a Separator. That is were the modified answer comes from.

edited May 23 '17 at 11:56

Community

1
1

answered Jan 19 '15 at 08:32

Greenonline

1,330
8
23
31

Split a list into a list of lists by condition

3 Answers3