19

I hope you can help... Let's assume I have following XML:

<data>
   <token>
      <sessionId>12345</sessionId>         
      <userId>john</userId>
      <moreInfo>
         <bla> .....
         </bla>
      </moreInfo>
   </token>
</data>

And I need this to become

<login:data xmlns:login="http://my.ns.uri">
       <login:token>
          <login:sessionId>12345</sessionId>         
          <login:userId>john</userId>
          <login:moreInfo>
             <login:bla> .....
             </login:bla>
          </login:moreInfo>
       </login:token>
    </login:data>

Can I do this with XSL? I did try but failed miserably ... Any help would be greatly appreciated!

Thanks, Jan

Boldewyn
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Jan
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3 Answers3

19

Use:

<xsl:stylesheet version="1.0"
 xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
 xmlns:login="http://my.ns.uri">
 <xsl:output omit-xml-declaration="yes" indent="yes"/>

 <xsl:template match="node()|@*">
  <xsl:copy>
   <xsl:apply-templates select="node()|@*"/>
  </xsl:copy>
 </xsl:template>

 <xsl:template match="*">
  <xsl:element name="login:{name()}" namespace="http://my.ns.uri">
    <xsl:copy-of select="namespace::*"/>
    <xsl:apply-templates select="node()|@*"/>
  </xsl:element>
 </xsl:template>
</xsl:stylesheet>

When this transformation is applied on the provided XML document, the wanted, correct result is produced:

<login:data xmlns:login="http://my.ns.uri">
   <login:token>
      <login:sessionId>12345</login:sessionId>
      <login:userId>john</login:userId>
      <login:moreInfo>
         <login:bla> .....
         </login:bla>
      </login:moreInfo>
   </login:token>
</login:data>
Dimitre Novatchev
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0
<xsl:template match="*">
  <xsl:element name="{local-name()}" namespace="http://my.ns.uri">
    <xsl:apply-templates />
  </xsl:element>
</xsl:template>
Boldewyn
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  • All right, I understand this. But how can I change the prefixes of all the elements? – Jan May 10 '10 at 13:56
  • Prefixes are something, that is quite fluid in XML. I mean, that the spec says explicitly, that they are *arbitrary*. So, your XSLT processor would be free to change them to whatever it likes. However, every (known to me) XSLT engine re-uses the prefixes that you wrote in your opening `` tag, if there aren't reasons to not do this (like XSLT's `exclude-result-prefix`). – Boldewyn May 10 '10 at 14:03
0

XSLT 2.0 is more efficient and compact. It supports to add namespaces to node directly. We don't need to define anything in the starting of stylesheet as well.

Here is the spec : creating namespace prefix

Use :

<xsl:stylesheet version="2.0"
  xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
 <xsl:output omit-xml-declaration="yes" indent="yes"/>
 <xsl:template match="*">
  <xsl:element name="login:{name()}" xmlns:login="http://my.ns.uri">
   <xsl:namespace name="login">http://my.ns.uri</xsl:namespace>
   <xsl:value-of select="node()"/>
   <xsl:apply-templates select="*"/>
  </xsl:element>
 </xsl:template>
</xsl:stylesheet>

It will give the output :

<login:data xmlns:login="http://my.ns.uri">
   <login:token>
      <login:sessionId>12345</login:sessionId>
      <login:userId>john</login:userId>
      <login:moreInfo>
         <login:bla> .....
         </login:bla>
      </login:moreInfo>
   </login:token>
</login:data>
Mandy
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