Printing out results of Json API Request on Java/Android

Question

I am using the following guide demonstrated by Konstantin Burov on a Stackoverflow post (Make an HTTP request with android):

First of all, request a permission to access network, add following to your manifest:

<uses-permission android:name="android.permission.INTERNET" />

Then the easiest way is to use Apache http client bundled with Android:

    HttpClient httpclient = new DefaultHttpClient();
    HttpResponse response = httpclient.execute(new HttpGet(URL));
    StatusLine statusLine = response.getStatusLine();
    if(statusLine.getStatusCode() == HttpStatus.SC_OK){
        ByteArrayOutputStream out = new ByteArrayOutputStream();
        response.getEntity().writeTo(out);
        out.close();
        String responseString = out.toString();
        //..more logic
    } else{
        //Closes the connection.
        response.getEntity().getContent().close();
        throw new IOException(statusLine.getReasonPhrase());
    }

If you want it to run on separate thread I'd recommend extending AsyncTask:

class RequestTask extends AsyncTask<String, String, String>{

    @Override
    protected String doInBackground(String... uri) {
        HttpClient httpclient = new DefaultHttpClient();
        HttpResponse response;
        String responseString = null;
        try {
            response = httpclient.execute(new HttpGet(uri[0]));
            StatusLine statusLine = response.getStatusLine();
            if(statusLine.getStatusCode() == HttpStatus.SC_OK){
                ByteArrayOutputStream out = new ByteArrayOutputStream();
                response.getEntity().writeTo(out);
                out.close();
                responseString = out.toString();
            } else{
                //Closes the connection.
                response.getEntity().getContent().close();
                throw new IOException(statusLine.getReasonPhrase());
            }
        } catch (ClientProtocolException e) {
            //TODO Handle problems..
        } catch (IOException e) {
            //TODO Handle problems..
        }
        return responseString;
    }

    @Override
    protected void onPostExecute(String result) {
        super.onPostExecute(result);
        //Do anything with response..
    }
}

You then can make a request by:

   new RequestTask().execute("http://stackoverflow.com");

My question is how do I now post the actual results in a string? All i'm getting is the address when I do new RequestTask().execute(url).toString();

score 0 · Accepted Answer · answered Jan 19 '15 at 23:38

Your response is delivered as an argument to onPostExecute(String). You're supposed to handle the response in this method. Be aware that onPostExecute(String) is run on the UI thread, so you cannot do lengthy operations as part of this method.

When you call new RequestTask().execute(url).toString(); you're simply invoking the toString() method of your AsyncTask (check the return value of execute(): it simply returns this, i.e. the AsyncTask that you're calling execute() on).

Printing out results of Json API Request on Java/Android

1 Answers1