I am getting the following php error

Question

This is the part of my code giving the problem.I tried to use isset but i think my syntax is incorrect. I still get the Notice: Undefined index: id.

if($_GET['id'] && $record['allusers'] != "Y"){
        $q2 = mysql_query("SELECT * from users WHERE alljobs = 'Y'");
        while($arr2 = mysql_fetch_assoc($q2)){
            $userjobs2[] = $arr2['id']; 
        }

It seems your $_GET["id"] is not exists. Create a check, is that key exists. `if (isset($_GET["id"]) ...` — vaso123, Jan 21 '15 at 14:34
**Please, [stop using `mysql_*` functions](http://stackoverflow.com/questions/12859942/why-shouldnt-i-use-mysql-functions-in-php).** They are no longer maintained and are [officially deprecated](https://wiki.php.net/rfc/mysql_deprecation). **Learn about [prepared statements](http://en.wikipedia.org/wiki/Prepared_statement)** instead, and **use [PDO](http://us1.php.net/pdo).** — Jay Blanchard, Jan 21 '15 at 14:35

score 0 · Accepted Answer · answered Jan 21 '15 at 14:34

Your code is correct this is not an Error it is a Notice to get rid of this you can use isset($_GET['id'])

if(isset($_GET['id']) && $record['allusers'] != "Y"){
        $q2 = mysql_query("SELECT * from users WHERE alljobs = 'Y'");
        while($arr2 = mysql_fetch_assoc($q2)){
            $userjobs2[] = $arr2['id']; 
        }
}

score 0 · Answer 2 · answered Jan 21 '15 at 14:34

0

$_GET['id'] won't return boolean. It will throw error if undefined/unset. Use isset().

if(isset($_GET['id']) && $record['allusers'] != 'Y') {
    // code...
}

answered Jan 21 '15 at 14:34

mehulmpt

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I am getting the following php error

2 Answers2