How to convert map to url query string?

Question

Do you know of any utility class/library, that can convert Map into URL-friendly query string?

Example:

I have a map:

"param1"=12,
"param2"="cat"

I want to get:

param1=12&param2=cat

final output

relativeUrl+param1=12&param2=cat

Answer 1

The most robust one I saw off-the-shelf is the URLEncodedUtils class from Apache Http Compoments (HttpClient 4.0).

The method URLEncodedUtils.format() is what you need.

It doesn't use map so you can have duplicate parameter names, like,

  a=1&a=2&b=3

Not that I recommend this kind of use of parameter names.

Answer 2

Here's something that I quickly wrote; I'm sure it can be improved upon.

import java.util.*;
import java.io.UnsupportedEncodingException;
import java.net.URLEncoder;

public class MapQuery {
    static String urlEncodeUTF8(String s) {
        try {
            return URLEncoder.encode(s, "UTF-8");
        } catch (UnsupportedEncodingException e) {
            throw new UnsupportedOperationException(e);
        }
    }
    static String urlEncodeUTF8(Map<?,?> map) {
        StringBuilder sb = new StringBuilder();
        for (Map.Entry<?,?> entry : map.entrySet()) {
            if (sb.length() > 0) {
                sb.append("&");
            }
            sb.append(String.format("%s=%s",
                urlEncodeUTF8(entry.getKey().toString()),
                urlEncodeUTF8(entry.getValue().toString())
            ));
        }
        return sb.toString();       
    }
    public static void main(String[] args) {
        Map<String,Object> map = new HashMap<String,Object>();
        map.put("p1", 12);
        map.put("p2", "cat");
        map.put("p3", "a & b");         
        System.out.println(urlEncodeUTF8(map));
        // prints "p3=a+%26+b&p2=cat&p1=12"
    }
}

Answer 3

I found a smooth solution using java 8 and polygenelubricants' solution.

parameters.entrySet().stream()
    .map(p -> urlEncodeUTF8(p.getKey()) + "=" + urlEncodeUTF8(p.getValue()))
    .reduce((p1, p2) -> p1 + "&" + p2)
    .orElse("");

Answer 4

In Spring Util, there is a better way..,

import org.springframework.util.LinkedMultiValueMap;
import org.springframework.util.MultiValueMap;
import org.springframework.util.concurrent.ListenableFuture;
import org.springframework.web.util.UriComponents;
import org.springframework.web.util.UriComponentsBuilder;

MultiValueMap<String, String> params = new LinkedMultiValueMap<String, String>();
params.add("key", key);
params.add("storeId", storeId);
params.add("orderId", orderId);
UriComponents uriComponents =     UriComponentsBuilder.fromHttpUrl("http://spsenthil.com/order").queryParams(params).build();
ListenableFuture<ResponseEntity<String>> responseFuture =     restTemplate.getForEntity(uriComponents.toUriString(), String.class);

Answer 5

Update June 2016

Felt compelled to add an answer having seen far too many SOF answers with dated or inadequate answers to very common problem - a good library and some solid example usage for both parse and format operations.

Use org.apache.httpcomponents.httpclient library. The library contains this org.apache.http.client.utils.URLEncodedUtils class utility.

For example, it is easy to download this dependency from Maven:

 <dependency>
    <groupId>org.apache.httpcomponents</groupId>
    <artifactId>httpclient</artifactId>
    <version>4.5</version>
 </dependency>

For my purposes I only needed to parse (read from query string to name-value pairs) and format (read from name-value pairs to query string) query strings. However, there are equivalents for doing the same with a URI (see commented out line below).

// Required imports

import org.apache.http.NameValuePair;
import org.apache.http.client.utils.URLEncodedUtils;
import java.io.UnsupportedEncodingException;
import java.net.URLDecoder;
import java.nio.charset.StandardCharsets;

// code snippet

public static void parseAndFormatExample() throws UnsupportedEncodingException {
        final String queryString = "nonce=12345&redirectCallbackUrl=http://www.bbc.co.uk";
        System.out.println(queryString);
        // => nonce=12345&redirectCallbackUrl=http://www.bbc.co.uk

        final List<NameValuePair> params =
                URLEncodedUtils.parse(queryString, StandardCharsets.UTF_8);
        // List<NameValuePair> params = URLEncodedUtils.parse(new URI(url), "UTF-8");

        for (final NameValuePair param : params) {
            System.out.println(param.getName() + " : " + param.getValue());
            // => nonce : 12345
            // => redirectCallbackUrl : http://www.bbc.co.uk
        }

        final String newQueryStringEncoded =
                URLEncodedUtils.format(params, StandardCharsets.UTF_8);


        // decode when printing to screen
        final String newQueryStringDecoded =
                URLDecoder.decode(newQueryStringEncoded, StandardCharsets.UTF_8.toString());
        System.out.println(newQueryStringDecoded);
        // => nonce=12345&redirectCallbackUrl=http://www.bbc.co.uk
    }

This library did exactly what I needed and was able to replace some hacked custom code.

Answer 6

If you actually want to build a complete URI, try URIBuilder from Apache Http Compoments (HttpClient 4).

This does not actually answer the question, but it answered the one I had when I found this question.

Answer 7

I wanted to build on @eclipse's answer using java 8 mapping and reducing.

 protected String formatQueryParams(Map<String, String> params) {
      return params.entrySet().stream()
          .map(p -> p.getKey() + "=" + p.getValue())
          .reduce((p1, p2) -> p1 + "&" + p2)
          .map(s -> "?" + s)
          .orElse("");
  }

The extra map operation takes the reduced string and puts a ? in front only if the string exists.

Answer 8

Another 'one class'/no dependency way of doing it, handling single/multiple:

import java.io.UnsupportedEncodingException;
import java.net.URLEncoder;
import java.util.ArrayList;
import java.util.Arrays;
import java.util.Iterator;
import java.util.LinkedHashMap;
import java.util.List;
import java.util.Map;
import java.util.Map.Entry;

public class UrlQueryString {
  private static final String DEFAULT_ENCODING = "UTF-8";

  public static String buildQueryString(final LinkedHashMap<String, Object> map) {
    try {
      final Iterator<Map.Entry<String, Object>> it = map.entrySet().iterator();
      final StringBuilder sb = new StringBuilder(map.size() * 8);
      while (it.hasNext()) {
        final Map.Entry<String, Object> entry = it.next();
        final String key = entry.getKey();
        if (key != null) {
          sb.append(URLEncoder.encode(key, DEFAULT_ENCODING));
          sb.append('=');
          final Object value = entry.getValue();
          final String valueAsString = value != null ? URLEncoder.encode(value.toString(), DEFAULT_ENCODING) : "";
          sb.append(valueAsString);
          if (it.hasNext()) {
            sb.append('&');
          }
        } else {
          // Do what you want...for example:
          assert false : String.format("Null key in query map: %s", map.entrySet());
        }
      }
      return sb.toString();
    } catch (final UnsupportedEncodingException e) {
      throw new UnsupportedOperationException(e);
    }
  }

  public static String buildQueryStringMulti(final LinkedHashMap<String, List<Object>> map) {
    try {
      final StringBuilder sb = new StringBuilder(map.size() * 8);
      for (final Iterator<Entry<String, List<Object>>> mapIterator = map.entrySet().iterator(); mapIterator.hasNext();) {
        final Entry<String, List<Object>> entry = mapIterator.next();
        final String key = entry.getKey();
        if (key != null) {
          final String keyEncoded = URLEncoder.encode(key, DEFAULT_ENCODING);
          final List<Object> values = entry.getValue();
          sb.append(keyEncoded);
          sb.append('=');
          if (values != null) {
            for (final Iterator<Object> listIt = values.iterator(); listIt.hasNext();) {
              final Object valueObject = listIt.next();
              sb.append(valueObject != null ? URLEncoder.encode(valueObject.toString(), DEFAULT_ENCODING) : "");
              if (listIt.hasNext()) {
                sb.append('&');
                sb.append(keyEncoded);
                sb.append('=');
              }
            }
          }
          if (mapIterator.hasNext()) {
            sb.append('&');
          }
        } else {
          // Do what you want...for example:
          assert false : String.format("Null key in query map: %s", map.entrySet());
        }
      }
      return sb.toString();
    } catch (final UnsupportedEncodingException e) {
      throw new UnsupportedOperationException(e);
    }
  }

  public static void main(final String[] args) {
    // Examples: could be turned into unit tests ...
    {
      final LinkedHashMap<String, Object> queryItems = new LinkedHashMap<String, Object>();
      queryItems.put("brand", "C&A");
      queryItems.put("count", null);
      queryItems.put("misc", 42);
      final String buildQueryString = buildQueryString(queryItems);
      System.out.println(buildQueryString);
    }
    {
      final LinkedHashMap<String, List<Object>> queryItems = new LinkedHashMap<String, List<Object>>();
      queryItems.put("usernames", new ArrayList<Object>(Arrays.asList(new String[] { "bob", "john" })));
      queryItems.put("nullValue", null);
      queryItems.put("misc", new ArrayList<Object>(Arrays.asList(new Integer[] { 1, 2, 3 })));
      final String buildQueryString = buildQueryStringMulti(queryItems);
      System.out.println(buildQueryString);
    }
  }
}

You may use either simple (easier to write in most cases) or multiple when required. Note that both can be combined by adding an ampersand... If you find any problems let me know in the comments.

Answer 9

This is the solution I implemented, using Java 8 and org.apache.http.client.URLEncodedUtils. It maps the entries of the map into a list of BasicNameValuePair and then uses Apache's URLEncodedUtils to turn that into a query string.

List<BasicNameValuePair> nameValuePairs = params.entrySet().stream()
   .map(entry -> new BasicNameValuePair(entry.getKey(), entry.getValue()))
   .collect(Collectors.toList());

URLEncodedUtils.format(nameValuePairs, Charset.forName("UTF-8"));

Answer 10

There's nothing built into Java to do this. But, hey, Java is a programming language, so. Let's program it!

map
.entrySet()
.stream()
.map(e -> e.getKey() + "=" + e.getValue())
.collect(Collectors.joining("&"))

This gives you param1=12&param2=cat. Now we need to join the URL and this bit together. You'd think you can just do: URL + "?" + theAbove but if the URL already contains a question mark, you have to join it all together with "&" instead. One way to check is to see if there's a question mark in the URL someplace already.

Also, I don't quite know what is in your map. If it's raw stuff, you probably have to safeguard the call to e.getKey() and e.getValue() with URLEncoder.encode or similar.

Yet another way to go is that you take a wider view. Are you trying to append a map's content to a URL, or... Are you trying to make an HTTP (S) request from a Java process with the stuff in the map as (additional) HTTP params? In the latter case, you can look into an HTTP library like OkHttp which has some nice APIs to do this job, then you can forego any need to mess about with that URL in the first place.

Answer 11

Using EntrySet and Streams:

map
  .entrySet()
  .stream()
  .map(e -> e.getKey() + "=" + e.getValue())
  .collect(Collectors.joining("&"));

Answer 12

You can use a Stream for this, but instead of appending query parameters myself I'd use a Uri.Builder. For example:

final Map<String, String> map = new HashMap<>();
map.put("param1", "cat");
map.put("param2", "12");

final Uri uri = 
    map.entrySet().stream().collect(
        () -> Uri.parse("relativeUrl").buildUpon(),
        (builder, e) -> builder.appendQueryParameter(e.getKey(), e.getValue()),
        (b1, b2) -> { throw new UnsupportedOperationException(); }
    ).build();

//Or, if you consider it more readable...
final Uri.Builder builder = Uri.parse("relativeUrl").buildUpon();
map.entrySet().forEach(e -> builder.appendQueryParameter(e.getKey(), e.getValue())
final Uri uri = builder.build();

//...    

assertEquals(Uri.parse("relativeUrl?param1=cat&param2=12"), uri);

Answer 13

Here's a simple kotlin solution:

fun Map<String, String>.toUrlParams(): String =
    entries.joinToString("&") {
        it.key.toUrlEncoded() + "=" + it.value.toUrlEncoded()
    }

fun String.toUrlEncoded(): String = URLEncoder.encode(
    this, StandardCharsets.UTF_8
)

Answer 14

To improve a little bit upon @eclipse's answer: In Javaland a request parameter map is usually represented as a Map<String, String[]>, a Map<String, List<String>> or possibly some kind of MultiValueMap<String, String> which is sort of the same thing. In any case: a parameter can usually have multiple values. A Java 8 solution would therefore be something along these lines:

public String getQueryString(HttpServletRequest request, String encoding) {
    Map<String, String[]> parameters = request.getParameterMap();

    return parameters.entrySet().stream()
            .flatMap(entry -> encodeMultiParameter(entry.getKey(), entry.getValue(), encoding))
            .reduce((param1, param2) -> param1 + "&" + param2)
            .orElse("");
}

private Stream<String> encodeMultiParameter(String key, String[] values, String encoding) {
    return Stream.of(values).map(value -> encodeSingleParameter(key, value, encoding));
}

private String encodeSingleParameter(String key, String value, String encoding) {
    return urlEncode(key, encoding) + "=" + urlEncode(value, encoding);
}

private String urlEncode(String value, String encoding) {
    try {
        return URLEncoder.encode(value, encoding);
    } catch (UnsupportedEncodingException e) {
        throw new IllegalArgumentException("Cannot url encode " + value, e);
    }
}

Answer 15

I make these functions than also send just the property name when the value is null.

public static String urlEncode(Map<?, ?> map) {
  return map.entrySet().stream().map(
      entry -> entry.getValue() == null
        ? urlEncode(entry.getKey())
        : urlEncode(entry.getKey()) + "=" + urlEncode(entry.getValue())
    ).collect(Collectors.joining("&"));
}

public static String urlEncode(Object obj) {
  return URLEncoder.encode(obj.toString(), StandardCharsets.UTF_8);
}

Answer 16

For multivalue map you can do like below (using java 8 stream api's)

Url encoding has been taken cared in this.

MultiValueMap<String, String> params =  new LinkedMultiValueMap<>();
String urlQueryString = params.entrySet()
            .stream()
            .flatMap(stringListEntry -> stringListEntry.getValue()
                    .stream()
                    .map(s -> UriUtils.encode(stringListEntry.getKey(), StandardCharsets.UTF_8.toString()) + "=" +
                            UriUtils.encode(s, StandardCharsets.UTF_8.toString())))
            .collect(Collectors.joining("&"));

Answer 17

If you need just the query string (not the whole URL) and you are using Spring Framework, you can do this:

import org.springframework.web.util.UriComponentsBuilder;

...

final String queryString = UriComponentsBuilder.newInstance()
    .queryParam("many", "7", "14", "21")
    .queryParam("single", "XYZ")
    .build()
    .toUri()
    .getQuery();

System.out.println(queryString);

the result is:

many=7&many=14&many=21&single=XYZ

Answer 18

Personally, I'd go for a solution like this, it's incredibly similar to the solution provided by @rzwitserloot, only subtle differences.

This solution is small, simple & clean, it requires very little in terms of dependencies, all of which are a part of the Java Util package.

Map<String, String> map = new HashMap<>();

map.put("param1", "12");
map.put("param2", "cat");

String output = "someUrl?";
output += map.entrySet()
    .stream()
    .map(x -> x.getKey() + "=" + x.getValue() + "&")
    .collect(Collectors.joining("&"));

System.out.println(output.substring(0, output.length() -1));

Answer 19

Kotlin

mapOf(
  "param1" to 12,
  "param2" to "cat"
).map { "${it.key}=${it.value}" }
  .joinToString("&")

Answer 20

a very lightweight answer it works for me

public static String queryStr(Map<String, String> data) throws UnsupportedEncodingException {
    StringBuilder query = new StringBuilder();
    for (Entry<String, String> entry : data.entrySet()) {
        if (query.length() > 0) {
          query.append('&');
        }
        query.append(entry.getKey()).append('=');
        query.append(URLEncoder.encode(entry.getValue(), "UTF-8"));
    }

    return query.toString();
}