How to construct a valid parameter for findNodeKeyByPath()?

Question

To access items in a SAP GUI GuiTree object, most methods need a key which identifies the node. To get such a key, you need the function findNodeKeyByPath(). The description says:

Return the node key for the given path (e.g. 2\1\2).
path The node path. STRING.

I need to get the first child of the first item in the tree. Using "0" throws an exception. Indexes of the root element seem to start at 1 instead of 0. Using "1" and "2" gives me correct keys.

But anything I try with a backslash does not work. "1\0" does not throw an exception, neither does "1\1". But both parameters return the key of node "1" and not of a subnode.

How do I need to construct the path in SilkTest (Silk4J, SAP) to get a valid key?

Answer 1

In Java, "\1" is the octal representation of ASCII character 0x01. See What does \1 represent. The string "1\\1" gives a valid path and returns the correct key.

However, the node must be visible, otherwise an empty string is returned. That means, you need the following code:

SapTree tree = ...; // initialize somewhere
String parentKey = tree.findNodeKeyByPath("1");
tree.expandNode(parentKey);
String key = tree.findNodeKeyByPath("1\\1");