Preserving order when copying elements using Deliverance / XPath

Question

How would I, using Deliverance & XPath (or CSS) selectors, select and copy list items .one and .three from each list below, but display them in the order of their parent list?

<ul id="a-wrapper">
   <li class="one"></li>
   <li class="two"></li>
   <li class="three"></li>
   <li class="four"></li>
</li>

<ul id="b-wrapper">
   <li class="one"></li>
   <li class="two"></li>
   <li class="three"></li>
   <li class="four"></li>
</ul>

    c,d,e,f,g etc....

The catch is it needs to use a href rule, eg: <prepend href="/blah/deblah" content="#x" theme="#y" />

Using the following just lists all the .one elements, then all the .three elements.

<prepend href="/blah/deblah" content=".one" theme="#y" />
<prepend href="/blah/deblah" content=".three" theme="#y" />

This is not an XPath question at all. Please edit and remove the xpath tag. — Dimitre Novatchev, May 13 '10 at 00:54
Accepted answer was XPath solution. Removal of XPath tag reversed. — Jon Hadley, May 17 '10 at 14:04

score 1 · Accepted Answer · answered May 13 '10 at 14:41

1

Not sure what you mean, but to grab all at once in source order use this XPATH:

//ul[@id='a-wrapper' or @id='b-wrapper']/li[@class='one' or @class='three']

answered May 13 '10 at 14:41

benglynn

26
1

Preserving order when copying elements using Deliverance / XPath

1 Answers1