Those 1,2 case are same in using anonymous function in Javascript ?
Normally, case 1 is seen easily.
Case 1 :
$('img:eq(0)').attr('src', ( function(){return '1'} ) ()); //works
console.log((function(){return '1'})()); //works
Case 2 :
$('img:eq(0)').attr('src', function(){return '2'}() ); //works
console.log(function(){return '2'}()); //works
Case 3 : (It seems jQuery parses its function)
$('img:eq(0)').attr('src', function(){return '3'}); //works
console.log(function(){return '3'}); //function
[in Chrome]
Thank you Felix Kling, But
In console,
(function(){alert('1');})() //works
function(){alert('2');}()// SyntaxError: Unexpected token (
Thank you AngularHarsh,
As you can see, there’s a catch. When the parser encounters the function keyword in the global scope or inside a function, it treats it as a function declaration (statement), and not as a function expression, by default. If you don’t explicitly tell the parser to expect an expression, it sees what it thinks to be a function declaration without a name and throws a SyntaxError exception because function declarations require a name.
in your attached link.
