Why isn't the following forEach array loop returning undefined?

Question

var amaList = ['announce', 'argue', 'demonstrate', 'express', 'hint', 'illustrate', 'imply', 'make', 'mean', 'pinpoint', 'point out', 'prove', 'reveal', 'show', 'signal', 'specify', 'suggest', 'attest', 'connote', 'denote', 'designatesta']

var hintList = amaList.forEach(function(s) {
  return s
})

console.log(hintList)

hintList logs undefined

What am I doing wrong?

Are you confusing `forEach` and `map` ? If not please precise what you expect and why. — Denys Séguret, Feb 02 '15 at 08:56
[Array.prototype.map()](https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Array/map) — Satpal, Feb 02 '15 at 08:57
maybe this issue could be useful: http://stackoverflow.com/questions/9329446/for-each-over-an-array-in-javascript — Marc Manzano, Feb 02 '15 at 09:01
`forEach` is not supposed to return anything. It simply executes the callback for its side effects. — Felix Kling, Feb 02 '15 at 09:11
@alexchenco Please [edit] your question and include what you expected to happen instead of getting `undefined`. — Madara's Ghost, Feb 02 '15 at 09:19

Amir Popovich · Accepted Answer · 2015-02-02T09:09:13.560

1

You probably want to use Array.prototype.map:

var hintList = amaList.map(function(item) {
     //do something with item and return the wanted item
});

Array.prototype.forEach doesn't return anything.

Here's an exampe for using forEach:

amaList.forEach(function(item){ 
     console.log(item);
});

edited Feb 02 '15 at 09:09

answered Feb 02 '15 at 09:02

Amir Popovich

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Why isn't the following forEach array loop returning undefined?

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