How to generate a random number

Question

I have to create a test for homework using Selenium IDE and create a scenario to generate a random number. I'm struggling with what I need to type and what field to type in.

What should I type in?: Command Target Value

Yes, you can generate random numbers in Selenium: http://stackoverflow.com/questions/161984/using-selenium-ide-with-random-values — Kiril, May 14 '10 at 05:53

score 20 · Answer 1 · edited Jul 26 '19 at 11:06

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_{(source: wisc.edu)}

edited Jul 26 '19 at 11:06

Glorfindel

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answered May 14 '10 at 00:37

OMG Ponies

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AH hahaha what a perfect response. – Mitch Dempsey May 14 '10 at 00:41

score 3 · Answer 2 · answered May 01 '13 at 18:09

i always use this to create random username and e-mails

storeEval > Math.round (Math.random() * 1357) > random
type > id=UserName > selenium${random}

and

storeEval > Math.round (Math.random() * 1357) > random
type > id=UserEmail > selenium${random}@am.com

i hope they can help you

score 1 · Answer 3 · edited Aug 06 '13 at 21:58

1

I use this often in my JUnit tests to create random inputs values.

int randNum = (int) (Math.random() * MAXVALUE);

edited Aug 06 '13 at 21:58

Jens Erat

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answered Aug 06 '13 at 21:39

usernz

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score 0 · Answer 4 · answered Jun 13 '13 at 13:41

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This is what I use:

Random rand = new Random(System.currentTimeMillis());
int num = rand.nextInt(range);

Range is the max number you want to return. Num will be something between 0 and range.

answered Jun 13 '13 at 13:41

Scott Helme

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score 0 · Answer 5 · answered Jun 17 '13 at 07:16

you can use

Random rndNum = new Random();    System.out.println("Num "+rndNum.nextInt());

for a single number like: Num -1597641332

or try

Random rndNum= new Random();    int rndNum1 = 0;

   for (int nbr = 1; nbr <= 3; nbr++) {
       rndNum1 = rndNum.nextInt();
       System.out.println("Number: " + rndNum1);    }

for multiple number of random numbers like

Number: -1891834125 Number: -1541629941 Number: -129634738

How to generate a random number

5 Answers5

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