.nextLine() jumps straight to next output

Question

I am on an Java encryption program where it prompts user to map his/her own String sequence from A-Z, 0-9, full stop, comma, exclamation mark and Space.

The programs runs like this:

User enter a String of different sequence from this:

String original= "ABCDEFGHIJKLMNOPQRSTUVWXYZ1234567890.,!";
String example= "!,.1234567890QWERTYUIOPASDFGHJKLZXCVBNM"

User will now choose to encrypt his own String.

Example output: 

Text to Encrypt: ENCRYPT
Encrypted Text: 2Q.TSEU

User can also choose to decrypt a String.

Text to Decrypt: 2Q.TSEU
Decrypted Text: ENCRYPT

However, I am unable to take in Space input for user's preferred String to encrypt.

I tried using .nextLine()instead of .next() but I met some bugs.

When I use String textToEncrypt= sc.nextLine(); this is the output I get.

Text to Encrypt: Encrypted Text: 
--------------------------------------------------------------------
(1-Encrypt) (2-Decrypt) (3-Quit):

Instead of allowing user to enter the text, it jumps to the next line immediately and goes back to the while loop which asks for user's choice.

It would really help if you could post a short but *complete* program (with proper indentation) which demonstrates the problem. — Jon Skeet, Feb 06 '15 at 11:38
possible duplicate of [Reading Strings next() and nextLine() Java](http://stackoverflow.com/questions/8873351/reading-strings-next-and-nextline-java) — user253751, Feb 06 '15 at 11:39

score 2 · Accepted Answer · answered Feb 06 '15 at 11:39

Use nextLine in all places :

while (run) {
  System.out.print("(1-Encrypt) (2-Decrypt) (3-Quit): ");
                option = sc.nextLine().charAt(0); // here
  if (option == '1') {

    System.out.print("\nText to Encrypt: ");
    String userEncrypt = sc.nextLine(); // and here
    ...

.nextLine() jumps straight to next output

1 Answers1