how is an "incomplete" initializer list parsed?

Asked Feb 07 '15 at 15:38

Active Feb 07 '15 at 15:38

Viewed 65 times

By mistake I added an extra comma in a brace initialization list, like this:

int main()
{
    int myArray[10]{0,}; // how is this parsed?
}

I know very well what myArray[10]{0} does, however adding this extra comma shouldn't be parseable in my opinion. I don't think it is a comma operator, as I haven't seen any comma operator having "nothing" on its right hand side. So why does it compile successfully? (both on g++ and clang++)

asked Feb 07 '15 at 15:38

vsoftco

55,410
12
139
252

3

Trailing comma in *braced-init-list* is ignored. See the grammar in **[dcl.init]/1** – Igor Tandetnik Feb 07 '15 at 15:40
FYI `int myArray[10]= {1,2,3,4,}; ` also compiles – P0W Feb 07 '15 at 15:41
@POW yes I know, I wonder why ;) – vsoftco Feb 07 '15 at 15:41
@IgorTandetnik thanks, this seem to be a very weird parsing scheme, I see no reason why is not just an error but just because the standard says so. – vsoftco Feb 07 '15 at 15:42
@vsoftco: It's for making code-generation easier. Whatever you might think of that. – Deduplicator Feb 07 '15 at 15:43
@vsoftco See [this](http://stackoverflow.com/q/7043372/1870232) – P0W Feb 07 '15 at 15:47
@POW, thanks, now I see I'm not the first one to have asked this question, although I didn't find the link before. The code generation "explanation" is a bit sketchy imo, but yes, it is an explanation. – vsoftco Feb 07 '15 at 15:52

how is an "incomplete" initializer list parsed?

0 Answers0