How to loop through a boost::mpl::list?

Question

This is as far as I've gotten,

#include <boost/mpl/list.hpp>
#include <algorithm>
namespace mpl = boost::mpl;

class RunAround {};
class HopUpAndDown {};
class Sleep {};

template<typename Instructions> int doThis();
template<> int doThis<RunAround>()    { /* run run run.. */ return 3; }
template<> int doThis<HopUpAndDown>() { /* hop hop hop.. */ return 2; }
template<> int doThis<Sleep>()        { /* zzz.. */ return -2; }


int main()
{
    typedef mpl::list<RunAround, HopUpAndDown, Sleep> acts;

//  std::for_each(mpl::begin<acts>::type, mpl::end<acts>::type, doThis<????>);

    return 0;
};

How do I complete this? (I don't know if I should be using std::for_each, just a guess based on another answer here)

Georg Fritzsche · Accepted Answer · 2010-05-15T15:36:36.083

14

Use mpl::for_each for runtime iteration over type lists. E.g.:

struct do_this_wrapper {
    template<typename U> void operator()(U) {
        doThis<U>();
    }
};

int main() {
    typedef boost::mpl::list<RunAround, HopUpAndDown, Sleep> acts;
    boost::mpl::for_each<acts>(do_this_wrapper());    
};

edited May 15 '10 at 15:36

answered May 15 '10 at 15:30

Georg Fritzsche

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1

Thanks - is there a way to do this using boost::bind instead of the wrapper object? – Kyle May 15 '10 at 15:46
2

@Kyle: I don't think so - i'm not aware of any utility in Boost.Bind that generates you the required functors with a templated `operator()`. – Georg Fritzsche May 15 '10 at 15:53
@GeorgFritzsche: Is there a way of making `do_this_wrapper` a lambda (as of C++11/14/17)? – Adi Shavit Sep 05 '16 at 12:27
1

@AdiShavit That should be possible with C++14s [generic lambdas](http://stackoverflow.com/a/17233649/168225). – Georg Fritzsche Oct 06 '16 at 10:48

How to loop through a boost::mpl::list?

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