Until statement/loop python?

Question

Is there an until statement or loop in python? This does not work:

x = 10
list = []
until x = 0:
    list.append(raw_input('Enter a word: '))
    x-=1

See also: [Is there a “do … until” in Python?](http://stackoverflow.com/questions/1662161/is-there-a-do-until-in-python) and [Repeat-Until loop in python or equivalent](http://stackoverflow.com/questions/16758807/repeat-until-loop-in-python-or-equivalent) — John1024, Feb 10 '15 at 04:03

score 1 · Accepted Answer · answered Feb 10 '15 at 03:55

1

The equivalent is a while x₁ != x₂ loop.

Thus, your code becomes:

x = 10
lst = [] #Note: do not use list as a variable name, it shadows the built-in
while x != 0:
    lst.append(raw_input('Enter a word: '))
    x-=1

answered Feb 10 '15 at 03:55

A.J. Uppal

19,117
6
45
76

score 1 · Answer 2 · answered Feb 10 '15 at 03:55

1

while x != 0:
    #do stuff

This will run until x == 0

answered Feb 10 '15 at 03:55

James Lemieux

720
1
9
26

score 1 · Answer 3 · answered Feb 10 '15 at 04:01

You don't really need to count how many times you're looping unless you're doing something with that variable. Instead, you can use a for loop that will fire up to 10 times instead:

li = []
for x in range(10):
    li.append(raw_input('Enter a word: '))

As an aside, don't use list as a variable name, as that masks the actual list method.

score 1 · Answer 4 · answered Feb 08 '16 at 22:37

Python emulates until loops with the iter(iterable, sentinel) idiom:

x = 10
list = []
for x in iter(lambda: x-1, 0):
    list.append(raw_input('Enter a word: '))

I was forced to construct a trivial lambda for demonstration purposes; here a simple range() would suffice, as as @Makoto suggested.

Until statement/loop python?

4 Answers4