in_array does not work correctly when dealing with strings

Question

This code:

var_dump(in_array("000", array(",00", ".00")));
var_dump(in_array("111", array(",11", ".11")));

output:

bool(true)
bool(false)

Why does the first line return true ?

Could it have anything to do with [this behaviour](http://php.net/manual/en/function.in-array.php#91911)? — summea, Feb 10 '15 at 17:07
I've edited your title. Please remember that "does not work" is a vague description of a problem for other people searching for the same problem! — sjagr, Feb 10 '15 at 17:14

Cfreak · Accepted Answer · 2015-02-10T17:14:52.603

10

It has to do with PHP's type coercion. The "000" essentially gets converted to just 0. To force it to use strict type checking, in_array() accepts a third parameter.

var_dump(in_array("000", array(",00", ".00"), true));

output:

bool(false)

EDIT: @andrekeller also pointed out the ".00" probably gets converted to int 0 as well. Moral of the story, don't trust PHP to get types right.

edited Feb 10 '15 at 17:14

answered Feb 10 '15 at 17:09

Cfreak

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I would have written something similar, +1 – davidkonrad Feb 10 '15 at 17:10
agreed, deleted my similar answer – André Keller Feb 10 '15 at 17:11
1

@andrekeller was going to upvote you too. You're answer is also correct as it mentions the .00 being converted as well. Knowing PHP its probably both – Cfreak Feb 10 '15 at 17:12
2

@Cfreak: well then update your answer, does not make sense have to almost identical answers – André Keller Feb 10 '15 at 17:13

in_array does not work correctly when dealing with strings

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