Printing 1 to 100 without using loops or condition in java

Question

I want to display 1 to 100 without using loops. I already tried storing 1-100 in array but it also requires use of loops.

With all due respect. This makes absolutely no sense. You will need atleast one "conditional check" to see if the value is 100. — TheLostMind, Feb 11 '15 at 07:19
The key here is recursion (try it). But as TheLostMind said, you'll need at least one conditional check. — Paco Abato, Feb 11 '15 at 07:20
`System.out.println("1");System.out.println("2");System.out.println("3");...System.out.println("99");System.out.println("100");` — piet.t, Feb 11 '15 at 07:20
@Pallav - You can do it using recursion as *Paco* says. But without *conditional* check. Nopes.. Note that using recursion is almost always *inefficient*. — TheLostMind, Feb 11 '15 at 07:21
Maybe [printing from a file stream](http://stackoverflow.com/a/2950638/205233) will do the trick. — Filburt, Feb 11 '15 at 07:21
Use Clojure code from java with (range 1 100) in it. Same trick can be done with Scala etc. — boucekv, Feb 11 '15 at 07:23
@Pallav You can also do `System.out.println("1,2,3,4,5..."); ` — Jens, Feb 11 '15 at 07:43
Marked it as exactly [Duplicate of Display numbers from 1 to 100 without loops or conditions](http://stackoverflow.com/questions/2044033/display-numbers-from-1-to-100-without-loops-or-conditions) — Suhaib Janjua, Feb 11 '15 at 07:53

Dmitry Bychenko · Answer 1 · 2015-02-11T08:06:52.527

1

Try this (Java 8)

IntStream.range(1, 100).forEach(n -> { System.out.println(n); });

However, implementation of range() as well as forEach() uses loops, so, the solution may be on the edge of cheating.

If you consider the code above as cheating, you can emulate loop, via, say, recursion:

private static void printIt(int n) {
  System.out.println(n);

  if (n < 100)
    printIt(n + 1);
}

...

printIt(1);

edited Feb 11 '15 at 08:06

answered Feb 11 '15 at 07:23

Dmitry Bychenko

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6

You are using a loop. OP ask for a solution with out using loops. – Jens Feb 11 '15 at 07:24
4

But that `forEach`... I mean... Technically speaking... It is still a loop ;D – Matt Clark Feb 11 '15 at 07:24
Eh... Technically, `forEach` is not a *loop* by itself, its a *method* which, however, uses a loop... Actually, `range()` should use loop as well. So the solution is on the edge of cheating – Dmitry Bychenko Feb 11 '15 at 07:54

score 0 · Answer 2 · answered Feb 11 '15 at 07:24

0

Use toString() method like this:

System.out.println(array.toString());

It converts array to this:

[1,2,3,4...]

http://docs.oracle.com/javase/7/docs/api/java/util/Arrays.html#toString(java.lang.Object[])

answered Feb 11 '15 at 07:24

Zlopez

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But you need a loop to fill the array. – Jens Feb 11 '15 at 07:29
You can initialize array like this: `int[] array = {1,2,3,4,5...}` – Zlopez Feb 11 '15 at 07:31
Than you cal also write 100 `System.out.println()` statements. – Jens Feb 11 '15 at 07:33
Yes you can, but this is shorter – Zlopez Feb 11 '15 at 07:38
if you will have it short you can use `System.out.println("1,2,3,4,5...");` – Jens Feb 11 '15 at 07:40
This looks like the right answer. – Zlopez Feb 11 '15 at 07:42

Suhaib Janjua · Answer 3 · 2015-02-11T07:45:01.823

0

Try this,

import java.util.Arrays;

Code

int[] array = new int[] { 1, 2, 3, ... , 100 };
System.out.println(Arrays.toString(array));

Output:

[1, 2, 3, 4, ... , 100]

Java.util.Arrays.toString(int[ ]) Method

edited Feb 11 '15 at 07:45

answered Feb 11 '15 at 07:31

Suhaib Janjua

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You have to declare an array 100 values if you want to print values without using any loop and condition. – Suhaib Janjua Feb 11 '15 at 07:55

score 0 · Answer 4 · answered Feb 11 '15 at 07:31

0

You never said it had to print them only once or that program had to terminate successfully:

public static void main(String args[])
{
    print(0);
}

private static void print(int i)
{
    System.out.println((i % 100) + 1);
    print(i+1);
}

answered Feb 11 '15 at 07:31

Mike Zboray

39,828
3
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score 0 · Answer 5 · answered Feb 11 '15 at 07:49

0

public static void main(String[] args) {
    print(100);
}

private static void print(int n) {
    if(n > 1) {
        print(n-1);
    }
    System.out.println(n);
}

answered Feb 11 '15 at 07:49

hack4m

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score -1 · Answer 6 · answered Feb 11 '15 at 07:33

-1

Try Below code

 public static void main(String[] args) {
    int[] i = {1,10,50};
    System.out.println(Arrays.toString(i));
  }

answered Feb 11 '15 at 07:33

Keval

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Printing 1 to 100 without using loops or condition in java

6 Answers6