How to receive Yaml content in an AJAX call?

Question

In my application, there is an endpoint that sends me the raw contents of a Yaml file in response to an AJAX call. I want to display them as they are in UI. The console throws an obvious error, which is for invalid JSON. How would I do it?

Update:

This is the snippet used for reading the file and sending the response.

filename = __file__ # Select your file here.                                
wrapper = FileWrapper(file(filename))
response = HttpResponse(wrapper, content_type='text/plain')
response['Content-Length'] = os.path.getsize(filename)
return response

Is there a way I could form a dictionary there with the contents of the file and then send the response?

score 0 · Accepted Answer · answered Feb 13 '15 at 12:12

0

From server, use jsonify on the raw content, pack it and ship it over to client.

repacked_json = json.dumps(raw_yaml_data) 
json_obj = json.loads(repacked_json)
return jsonify(result = json_obj)

answered Feb 13 '15 at 12:12

Sidmeister

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The server is Python-Django, and it uses Django Rest Framework, if that helps! – Rutwick Gangurde Feb 13 '15 at 12:14
Okay, let me ask the backend guy to try it. Thanks! – Rutwick Gangurde Feb 13 '15 at 12:15
1

Django Rest Framework also supports Content Negotiation. Try asking the service endpoint for `application/json` and you might find that you get it. – Jamie Dixon Feb 13 '15 at 12:17
I'm editing my question and adding the Python code that is used for sending the file contents. – Rutwick Gangurde Feb 13 '15 at 12:30
You can take a look at this link here [link](http://stackoverflow.com/questions/1773805/how-can-i-parse-a-yaml-file) – Sidmeister Feb 13 '15 at 12:35
1
We used `json.dumps` and read the file using `file.read()`. Sent it across as `application/json` and then used `
` to display it! Thanks all you guys!
– Rutwick Gangurde Feb 13 '15 at 16:07

How to receive Yaml content in an AJAX call?

1 Answers1