Initialize array to my class c++

Question

I,m this class :

class Foo {
private:
    Objet grid;
    static Player *players[2];
public:
    Foo(int len, string ps1, string ps2);
};

When i do this :

Foo::Foo(int len, string ps1, string ps2){
    grid.setLen(len);
    players[0] = new Ange(ps1, grid.getLen()/2, grid.getLen/2);
    players[1] = new Demon(ps2);
}

Player is a class abstract and Ange et Demon herited to class Player

I'm this error to xCodes when i compile

Undefined symbols for architecture x86_64: "Partie::joueurs", referenced from: Partie::Partie(int, std::__1::basic_string, std::__1::allocator >, std::__1::basic_string, std::__1::allocator >) in Partie.o ld: symbol(s) not found for architecture x86_64 clang: error: linker command failed with exit code 1 (use -v to see invocation)

help me please !!!

Excuse my english i'm french

You have an undefined virtual method. Which is required for class construction. All virtual methods (not pure) must be defined somewhere. — Valeri Atamaniouk, Feb 13 '15 at 22:20
@ValeriAtamaniouk Where exactly do you see a virtual member in that code? — Captain Obvlious, Feb 13 '15 at 22:22
Those errors have nothing to do with that code. Can you show the actual code? — mjs, Feb 13 '15 at 22:23
Hoo I'm sorry I do not know why I'm gonna put that same static I deleted it and there it Works — Darkness007, Feb 13 '15 at 22:23
@CaptainObvlious That is my wild guess, as I don't speak French... But it is likely you are right and I'm not. — Valeri Atamaniouk, Feb 13 '15 at 22:27

score 1 · Accepted Answer · answered Feb 13 '15 at 22:23

The static member variable is only declared, you need to define it as well.

It's simplest done by adding, in a source file somewhere:

Player *Foo::players[2];

Though you should not initialize static member variables in the constructor, what do you think would happen if you create Two (or more) Foo objects?

Initialize array to my class c++

1 Answers1