Compare 2 arrays and if match return 1

Question

When i console two arrays below is how it look

aa=  [0: "349",1: "810",2: "863",3: "657",4: "602",5: "317",6: "665",7: "865",8: "624",9: "805",10: "887",11: "659"];

bb=[0: "349", 1: ""];

cc=find_flight(aa,bb);

in both arrays 349 is matching, once match it should return 1. Below is how i tried

function find_flight(aa,bb)
    {
        if(a2.toString() == a1.toString())
        {
                return true;
        }
    }


console.log(aa+'-'+bb);

Output: 349,810,863,657,602,317,665,865,624,805,887,659-349,

Its not matching can any one give solution !!!!

You are testing both arrays are exactly equals in this way. It is not right because they have different values. You gotta try another logic — nanndoj, Feb 14 '15 at 19:56

void · Accepted Answer · 2015-02-14T20:41:25.030

1

function find_flight(a,b)
{
var check  = false;
a.forEach(function(x) { 
   b.forEach(function(y) { 
       //console.log(x+"  "+y +"   "+(x==y?1:0));
       if (x==y) { check=true; } 
   });
});
return check;
}

var aa= [1,2,3,4,5,6];
var bb= [0,9,8,7, 4];

Use it like

console.log(find_flight(aa,bb));

edited Feb 14 '15 at 20:41

answered Feb 14 '15 at 20:00

void

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349-349 is matching but return true; is not returning, may be it is inside the array – sivashanker Feb 14 '15 at 20:34

score 0 · Answer 2 · answered Feb 14 '15 at 19:59

One approach would be this:

found=false; 
aa.forEach(function(e) { 
   bb.forEach(function(e2) { 
     if (e === e2) { found=true; } 
   });
});

I used this to initialize the arrays as my console did not accept your syntax.

aa = ["349","810","863","657","602","317","665","865","624","805","887","659"];
bb = ["349",""];

Compare 2 arrays and if match return 1

2 Answers2