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In my Python code, I have a part where I would like to repeatedly print a question if it doesn't match what I want it to.

name1 = input("A male name (protagonist): ")
    if name1.endswith (('ly', 's')):
        print("Sorry mate, this doesn't seem to be a proper noun. Try it again.")
        name1 = input("A male name (protagonist): ")

How do I make it repeatedly print out name1 if it ends with 'ly' or 's'?

Cooper Timewell
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  • This is very simple: change 'if' to 'while'. Are you really unfamiliar with loops? If so you might want to invest in a Python beginner's guide, or a general introduction to programming. – zwol Feb 16 '15 at 02:18
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    Also, I can think of several male names that end in 's' and 'ly'. – zwol Feb 16 '15 at 02:19

2 Answers2

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You can use a while loop. While loops will continuously perform something as long as it's specified condition is true.

If you don't want a name that ends with ly or s, you can make a while loop like so:

while True:
    name1 = input("A male name (protagonist): ")
    if name1.endswith ('ly', 's'):
        print("Sorry mate, this doesn't seem to be a proper noun. Try again. ")
    else:
        break # This will exit the loop, when you have a name that doesn't satisfy the condition above

I should also mention that because the if statement was satisfied, it will restart the loop. Once the name does not end with ly or s, it will move to the else block, which will come out of the loop. Note that the break is the word that forces out of the loop.

Zizouz212
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1

I think this is what you are after:

while True:
    name1 = input("A male name (protagonist): ")
    if name1.endswith(('ly', 's')):
        print("Sorry mate, this doesn't seem to be a proper noun. Try it again.")
        continue
    break

print("Input name is:", name1)

This will loop over until if name1.endswith(('ly', 's')) is true.

Marcin
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  • @AvinashRaj It wont. `if name1.endswith(('ly', 's'))` must be true for `continue` to execute. – Marcin Feb 16 '15 at 02:24